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PIT_PIT [208]
4 years ago
12

Detrital rocks are ____.

Physics
1 answer:
Alika [10]4 years ago
4 0
Made from other rocks

:))
merry christmas
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What is 1.2 kg converted into mg.<br> I need to know for step by step please?
astra-53 [7]
Here’s a good photo to reference when converting in the metric system.

Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.

We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.

1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.

So our final answer would be 1,200,000mg.
4 0
4 years ago
You own a high speed digital camera that can take a picture every 0.5 seconds. You decide to take a picture every 0.5 seconds of
Vesnalui [34]

-- There is no need to develop the pictures.  They are available immediately in a digital camera.

-- There is no change in the teacher from one picture to the next.

-- The distance the watermelon falls from the teacher in each new picture is more in each picture than in the picture before it. (C)


8 0
3 years ago
AuniformsphericalshellofmassM=4.5kgandradiusR=8.5cmcan rotate about a fixed vertical axis on frictionless bearings. A massless,
Kazeer [188]

Answer:

v=1.42\frac{m}{s}

Explanation:

There is no friction in the physical system. Thus, according to the law of conservation of energy, recall that the object is released from rest:

\Delta E=0\\U=K_R+K_T\\mgh=\frac{I_p\omega_p^2}{2}+\frac{I_s\omega_s^2}{2}+\frac{mv^2}{2}

Recall that the moment of inertia of a sphere is I_s=\frac{2MR^2}{3}. The angular speed of the pulley is \omega_p=\frac{v}{r} and the angular speed of the sphere is \omega_s=\frac{v}{R}. So, we replace:

mgh=\frac{I_pv^2}{2r^2}+\frac{2MR^2}{3}\frac{v^2}{2R^2}+\frac{mv^2}{2}\\mgh=v^2(\frac{I_p}{2r^2}+\frac{M}{3}+\frac{m}{2})\\v^2=\frac{mgh}{\frac{I_p}{2r^2}+\frac{M}{3}+\frac{m}{2}}\\\\v=\sqrt{\frac{(0.6kg)(9.8\frac{m}{s^2})(0.82m)}{\frac{3*10^{-3}kg\cdot m^2}{2(0.05m)^2}+\frac{4.5kg}{3}+\frac{0.6kg}{2}}}\\v=1.42\frac{m}{s}

5 0
4 years ago
Write down the role played by four digestive juices in digestion and the
valentinak56 [21]

Answer:

Digestive juices secreted by various organs such as salivary glands in the mouth, stomach, liver and pancreas help in the process of digestion of food. Saliva secreted by the salivary glands in the mouth aids in the breakdown of starch present in the food to simple sugar

Explanation:

3 0
3 years ago
A bob of mass m = 0.250 kg is suspended from a fixed point with a massless string of length L = 22.0 cm. You will investigate th
katen-ka-za [31]

To solve the problem, it is necessary to use the concepts of gravitational force, centripetal force and trigonometric components that can be extrapolated from the statement.

By definition we know that the Force of Gravity is given by

F_g=mg

Where,

m= Mass

g = Gravitational Acceleration

The centripetal force is given by,

F_c = \frac{mv^2}{R}

Where,

m = Mass

v = Velocity

R = Radius

For the case described in the problem, the Force of gravity the net component would be given by sin?, While for the centripetal force the net component is in the horizontal direction, therefore it corresponds to the cos\theta

Then,

F_g = mg sin\theta

F_c = \frac{mv^2}{r}cos\theta

From the radius we have its length but not the net height, which would be given by

r = L sin\theta

So equating the equations we have to

F_g = F_c

mg sin\theta=\frac{mv^2}{r}cos\theta

mg sin\theta=\frac{mv^2}{Lsin\theta}cos\theta

Re-arrange to find v,

v = \sqrt{\frac{gLsin^2\theta}{cos\theta}}

Replacing with our values

v = \sqrt{\frac{(9.8)(22*10^{-2})(sin^2 24)}{cos24}}

v = 0.624

Therefore the tangential velocity of the mass is 0.624m/s

5 0
4 years ago
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