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Galina-37 [17]
3 years ago
10

using the water cycle diagram, match the number with the following; condensation runoff [precipitation and evaporation. once you

've identified the process for each number, explain how water moves and changes form in each step (you only need to do this for the 4 basic steps)

Chemistry
1 answer:
Oksanka [162]3 years ago
4 0

Answer:

1. Evaporation

2. Condensation

3. Precipitation

4. Runoff

Explanation:

The water cycle shows how water moves on the earth as it passes through different phases.

Water on land is stored in oceans, rivers and other water bodies. This water coupled with those in plants and animals are turned into vapor through EVAPORATION. Evaporation facilitates the movement of water on the surface into the atmosphere.

In the atmosphere, the vapor condenses on dust particles found up there. The vapors forms a nuclei around the dust particles and water condenses at the saturated vapor pressure. This forms cloud.

As the water collects more and more, gravity forces the water to fall in form of PRECIPITATION. The precipitation can be in form of snow or rainfall.

When precipitation occurs, they move on the surface as SURFACE RUNOFFS. Some of the runoff goes back into oceans and rivers. Others infiltrates into the ground and collects in the ground water pool under the subsurface. Subsurface water can also get into into other water bodies when the water table coincides with the steam level.

The water in these bodies can then go into the cycle again. The sun is the source of energy for this process.

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An aqueous solution containing 9.82 g9.82 g of lead(II) nitrate is added to an aqueous solution containing 5.76 g5.76 g of potas
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Answer:

  • The limiting reactant is lead(II) nitrate.
  • 7.20 g of precipitate are formed.
  • 1.9 g of the excess reactant remain.

Explanation:

The reaction that takes place is:

  • Pb(NO₃)₂(aq) + 2KCl(aq) → PbCl₂(s) + 2KNO₃(aq)

With a percent yield of 87.5%.

To determine the limiting reactant, first we <u>convert the masses of each reactant to moles</u>, using their molar mass:

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Looking at the stoichiometric coefficients, we see that 1 mol of Pb(NO₃)₂ would react completely with 2 moles of KCl. Following that logic, 0.0296 mol Pb(NO₃)₂ would react completely with (2x0.0296) 0.0592 mol of KCl. We have more than that amount of KCl, this means KCl is the reactant in excess and Pb(NO₃)₂ is the limiting reactant.

To calculate the mass of precipitate (PbCl₂) formed, we <u>use the moles of the limiting reactant</u>:

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- Keeping in mind the reaction yield, the moles of Pb(NO₃)₂ that would react are:

  • 0.0296 mol Pb(NO₃)₂ * 87.5/100 = 0.0259 mol Pb(NO₃)₂

Now we <u>convert that amount to moles of KCl and finally into grams of KCl</u>:

  • 0.0259 mol Pb(NO₃)₂ \frac{2molKCl}{1molPb(NO_{3})_2} * \frac{74.55g}{1molKCl} = 3.86 g KCl

3.86 g of KCl would react, so the amount remaining would be:

  • 5.76 - 3.86 = 1.9 g KCl

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