There would be 2 which would be on the oxygen
It requires 60 mL of 0.20 M sodium hydroxide
to neutralize 25 mL of carbonic acid
, hence the carbonate ions concentration is
.
Given:
Reaction:
volume
Volume
Molarity
moles
moles 
To find:
Molarity
Solution:
Using the neutralization reaction:

Calculating the
:

Therefore, the concentration of carbonic acid is "0.24M".
Learn more about the concentration:
brainly.com/question/9889034
Answer:
350 J
Explanation:
The law of conservation of energy states that energy can neither be created nor destroyed but can only be converted from one form to another. This means that in a system, energy is not lost.
In this question, an unlit match contains approximately 1,000 J of chemical energy. When lit, thermal and light energy are emitted i.e. it gets converted to light and heat energy. If the thermal energy emitted was measured to be 400J, and the remaining match still contains 250J of chemical energy, then:
The amount of light energy emitted will be:
Total chemical energy (1000J) - {Remaining chemical energy (250J) + emitted thermal energy (400J)}
= 1000 - (400 + 250)
= 1000 - 650
= 350
Hence, the amount of light energy emitted is 350J
Note that, the amount of energy converted (thermal and light) and remaining chemical energy still equates the total chemical energy in the match.
Answer:
22.35 g of (NH₄)₃PO₄ will be produced by 7.5 g of ammonia.
Explanation:
H₃PO₄ + 3NH₃ → (NH₄)₃PO₄
H₃PO₄: 98 g/mol
NH₃: 17 g/mol
(NH₄)₃PO₄: 149 g/mol
17 g NH₃ _________ 1 mol
7.5 g NH₃ __________ x
x = 0.44 mol NH₃
3 mol NH₃ __________ 1 mol (NH₄)₃PO₄
0.44 mol NH₃ _________ y
y = 0.15 mol (NH₄)₃PO₄
1 mol (NH₄)₃PO₄ ____________ 149 g
0.15 mol (NH₄)₃PO₄ __________ z
z = 22.35 g (NH₄)₃PO₄
The grams of 22.9 % sugar solution that contain 68.5 g of sugar is 299.13 g of solution
<u><em>calculation</em></u>
22.9% means that there are 22.9 g of sugar in 100 g of solution.
what about 68.5 g of sugar
- <em>by cross multiplication</em>
=[(68.5 g sugar x 100 g solution) /22.9 g sugar] =299.13 g of solution
Nb; <em>g sugar cancel each other</em>