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koban [17]
3 years ago
5

Suppose that units of force, length, and time are chosen such that the density of water and the acceleration of gravity are both

of unit magnitude. If the pound is taken as the unit of force, what are the sizes of the units of length and time?
Engineering
1 answer:
k0ka [10]3 years ago
3 0

Answer: So a 1 pound = 0.453592kg

the density of the water is D= 997 kg/m^{3} so we need to use replace the kg with pounds with 2.20462 pounds = 1kg.

then D = 2.20462*997 pounds/m^{3}

and we want to make this equal to one changing the metters for other thing.

we need to replace x^{3} with 2.020462*997 meters qube.

then our new metters variable x = 12.6meters.

now g = 9.8 meters for second square.

in our new lenght variable x.

g = 12.6*9.8 x for second square.

so if y is our new time variable

y^{2} = 12.6*9.8 seconds square. so y = 11.1seconds

so the units of length are x = 12.6 meters and for time y = 11.1 seconds.

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Para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al
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Answer:

Se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

Explanation:

Dado que para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al vacío, y en el evaporador se elimina el agua necesaria para que el jugo salga con una concentración del 60% de peso de sólidos, si se introducen al proceso 1000 kg/h de jugo diluido, para calcular la cantidad de agua evaporada y de jugo concentrado saliente se debe realizar el siguiente cálculo;

1000 x 0.07 = 70

60 = 70

100 = X

100 x 70 / 60 = X

7000 / 60 = X

116.66 = X

Por lo tanto, se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

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Read 2 more answers
The diffusion coefficients for iron in nickel are given at two temperatures:T (K)D (m2/s)12739.4 × 10–1614732.4 × 10–14(a) Deter
hram777 [196]

Answer:

The diffusion coefficients for iron in nickel are given at two temperatures:

T (K)        1273          1473

D (m^{2}/s) 9.4 × 10^{-16}    2.4 × 10^{-14}

(a) Determine the values of Do and the activation energy Qd.

(b) What is the magnitude of D at 1100°C (1373 K)?

<em>A </em>

<em>The pre-exponential factor Do = 2.1 x </em>10^{-16}<em></em>

<em>The activation energy Qd = 252,609 J/mol</em>

<em>B</em>

<em>The diffusion coefficient D= 5.14 x </em>10^{-15}<em></em>

Explanation:

The full explanation is contained in the attached images;

5 0
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