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stealth61 [152]
3 years ago
8

A 50 g ice cube can slide without friction up and down a 30â slope. the ice cube is pressed against a spring at the bottom of th

e slope, compressing the spring 10 cm. the spring constant is 25 n/m. when the ice cube is released, what total distance will it travel up the slope before reversing direction?
Physics
1 answer:
vfiekz [6]3 years ago
4 0
Fk= mgcostheta * coefficient of friction
Fk= (.05kg)(9.80)(cos30)(.20)=.085 N

change in thermal energy= Fk* distance covered up slope (d)
change in thermal energy = .085 * d

 the final height so y=dsin30

Kf + Uf + change in thermal energy = Ki + Ui

(.05kg)(9.80)(dsin30) + (.085d) = (.5)(25 N/m)(.1m)^2
 
d= .379 m = 37.9 cm


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    The current on the rod is  I  = 4.1 \ A

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        F_ k  =  B*  I  *  L

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7 0
3 years ago
Check all that apply. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic
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The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Explanation:

The magnitude of the magnetic force exerted on a current-carrying wire due to a magnetic field is given by

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According to eq.(1), we see that the statement:

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is correct, because when the current is perpendicular to the magnetic field, \theta=90^{\circ}, sin \theta = 1 and the force is maximum.

Moreover, according to (2), we also see that the statements

<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. "</em>

<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. "</em>

because F (the force) is perpendicular to both the magnetic field and the current.

5 0
3 years ago
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