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Mariulka [41]
3 years ago
11

which unit of measure would scientist use to measure the thickness of rock layer, created as a result of volcanic activity

Physics
2 answers:
Marina CMI [18]3 years ago
7 0

A scientist would use a unit of length appropriate for the magnitude of what he or she is measuring. In this case, since rock is built up very slowly, they would probably use millimetres or centimetres. In some cases they may use meters. 

There you go.

frozen [14]3 years ago
3 0
A scientist would use a unit of length appropriate for the magnitude of what he or she is measuring. In this case, since rock is built up very slowly, they would probably use millimetres or centimetres. In some cases they may use meters. 
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A scientist measures the growth of a bamboo plant over time. The table above shows the results. What is the best interference fo
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(B) 2.25cm

<u>Explanation:</u>

Given:

At 40 hours, the height of the bamboo plant is 2.1cm

At 50 hours, the height of the bamboo plant is 2.4cm

Height of the bamboo plant after 45 hours = ?

The difference in length from 40 to 50 hours = 2.4 - 2.1cm

                                                                      = 0.3 cm

Mean of 40 and 50 is 45.

Thus,

At 45 hours, the height will increase by 0.3/2

                                                         = 0.15 cm

Height at 45 hour = 2.1 + 0.15cm

                           = 2.25cm

Therefore, the height of the plant after 45 hours is 2.25cm

7 0
3 years ago
George saves 18% of his total gross weekly earnings from his two part-time jobs he earns $6.25 per hour from one part time job a
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Weekly wages and the amount saved each week

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A person that is sleeping on her stomach rolls over so that she is now sleeping on her back. The person moved from the ________
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c. prone; supine

Explanation:

3 0
1 year ago
If the phase of the vibrating sources was changed so that they were vibrating completely out of phase, what effect would this ha
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Answer:

There would be complete destructive interference.

Explanation:

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Since this is the case, the crest of the one source meets the trough of the other, this causes the resultant vibrational wave to cancel out, thus producing a destructive interference pattern.

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4 0
3 years ago
A rod of length Lo moves iwth a speed v along the horizontal direction. The rod makes an angle of (θ)0 with respect to the x' ax
Colt1911 [192]

Answer:

From the question we are told that

  The length of the rod is  L_o

    The  speed is  v  

     The angle made by the rod is  \theta

     

Generally the x-component of the rod's length is  

     L_x =  L_o cos (\theta )

Generally the length of the rod along the x-axis  as seen by the observer, is mathematically defined by the theory of  relativity as

       L_xo  =  L_x  \sqrt{1  - \frac{v^2}{c^2} }

=>     L_xo  =  [L_o cos (\theta )]  \sqrt{1  - \frac{v^2}{c^2} }

Generally the y-component of the rods length  is mathematically represented as

      L_y  =  L_o  sin (\theta)

Generally the length of the rod along the y-axis  as seen by the observer, is   also equivalent to the actual  length of the rod along the y-axis i.e L_y

    Generally the resultant length of the rod as seen by the observer is mathematically represented as

     L_r  =  \sqrt{ L_{xo} ^2 + L_y^2}

=>  L_r  = \sqrt{[ (L_o cos(\theta) [\sqrt{1 - \frac{v^2}{c^2} }\ \ ]^2+ L_o sin(\theta )^2)}

=>  L_r= \sqrt{ (L_o cos(\theta)^2 * [ \sqrt{1 - \frac{v^2}{c^2} } ]^2 + (L_o sin(\theta))^2}

=>   L_r  = \sqrt{(L_o cos(\theta) ^2 [1 - \frac{v^2}{c^2} ] +(L_o sin(\theta))^2}

=> L_r =  \sqrt{L_o^2 * cos^2(\theta)  [1 - \frac{v^2 }{c^2} ]+ L_o^2 * sin(\theta)^2}

=> L_r  =  \sqrt{ [cos^2\theta +sin^2\theta ]- \frac{v^2 }{c^2}cos^2 \theta }

=> L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }

Hence the length of the rod as measured by a stationary observer is

       L_r = L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }

   Generally the angle made is mathematically represented

tan(\theta) =  \frac{L_y}{L_x}

=>  tan {\theta } =  \frac{L_o sin(\theta )}{ (L_o cos(\theta ))\sqrt{ 1 -\frac{v^2}{c^2} } }

=> tan(\theta ) =  \frac{tan\theta}{\sqrt{1 - \frac{v^2}{c^2} } }

Explanation:

     

     

       

7 0
3 years ago
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