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Mariulka [41]
3 years ago
11

which unit of measure would scientist use to measure the thickness of rock layer, created as a result of volcanic activity

Physics
2 answers:
Marina CMI [18]3 years ago
7 0

A scientist would use a unit of length appropriate for the magnitude of what he or she is measuring. In this case, since rock is built up very slowly, they would probably use millimetres or centimetres. In some cases they may use meters. 

There you go.

frozen [14]3 years ago
3 0
A scientist would use a unit of length appropriate for the magnitude of what he or she is measuring. In this case, since rock is built up very slowly, they would probably use millimetres or centimetres. In some cases they may use meters. 
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A nonconducting container filled with 25 kg of water at 23°C is fitted with a stirrer, which is made to turn by gravity acting o
Paul [167]

Explanation:

Given that,

Weight of water = 25 kg

Temperature = 23°C

Weight of mass = 32 kg

Distance = 5 m

(a). We need to calculate the amount of work done on the water

Using formula of work done

W=mgh

W=32\times9.8\times5

W=1568\ J

The amount of work done on the water is 1568 J.

(b). We need to calculate the internal-energy change of the water

Using formula of internal energy

The change in internal energy of the water equal to the amount of the  work done on the water.

\Delta U=W

\Delta U=1568\ J

The  change in internal energy is 1568 J.

(c). We need to calculate the final temperature of the water

Using formula of the change internal energy

\Delta U=mc_{p}\Delta T

\Delta U=mc_{p}(T_{2}-T_{1})

T_{2}=T_{1}+\dfrac{\Delta U}{mc_{p}}

T_{2}=23+\dfrac{1568}{25\times4.18\times10^{3}}

T_{2}=23.01^{\circ}\ C

The final temperature of the water is 23.01°C.

(d). The amount of heat removed from the water to return it to it initial temperature is the change in internal energy.

The amount of heat is 1568 J.

Hence, This is the required solution.

6 0
3 years ago
Real bodies emit and absorb more radiation than a blackbody at the same temperature. True or False
monitta

Answer: False

Explanation:

Relative to the concept of radiations, a black body is an object capable of absorbing any form of electromagnetic radiation irrespective of its frequency or angle of incidence when incident on such object.

However, the same cannot be said about real bodies as real bodies are those which reflect all rays incident on them completely and uniformly in all directions.

One very important characteristic of black bodies is that they are ideal emmiters.

The concept of emmisivity is brought about by the existence of real bodies .

This is due to the fact that they are only able to emit radiation at a fraction of the black body energy levels.

Please note that by convention, the emmisivity of a real body is always less thaan 1.

As such they are not able to emit as much radiation as a black body at the same temperature.

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Lyrx [107]

Answer:

you still there?

Explanation:

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With your hand parallel to the floor and your palm upright, you raise a 3-kg book upward with an acceleration of 2 m/s2. what is
kirza4 [7]

35N i don´t know why

3 0
3 years ago
Read 2 more answers
How does gravity and density affect weight
frozen [14]
<span> </span>

Gravity affects weight because gravity creates weight. Objects have mass, which is defined as how much matter an object contains. Weight is defined as the pull of gravity on mass.

<span> The relation between weight and gravitational pull is such that, when on another celestial body, the difference in gravity would alter a person's weight. The Earth's moon, for example, has a gravitational field that is 0.165 times the pull on earth. A person who weighs 170 pounds on Earth would only weigh 28.05 pounds on the moon. This is why during the moon landing videos, people on earth viewed the astronauts taking large, bounding steps. With very little weight, it was easy for them to push off the ground.</span>
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