Answer:
1. The gaming company installs games for an arcade in the set of a movie
2. moviemakers might give permission to make a game based on the movie.
3. Advertisements on a game the moviemakers might get a percentage of the money made on a game because there are characters from the movie on the box saying "I played this game and it was awesome,"
Hope this helped! :)
Explanation:
Answer:
1) <em>4.41 * 10^-4 kw </em>
<em>2) </em>2.20 * 10^-4 kw
Explanation:
Given data:
Filter = 500 m^3/min
dust velocity = 3g/m^3
bag ; length = 3 m , diameter = 0.13 m
change in pressure = 1 kPa
efficiency = 60%
<u>1) Calculate the Fan power </u>
First :
Calculate the total dust loading = 3 * 500 = 1500 g
To determine the Fan power we will apply the relation
= 
<em>fan power ( </em>
)<em> = 4.41 * 10^-4 kw </em>
<u>2) calculate power drawn </u>
change in P = 6 atm = 6 * 10^5 pa
efficiency compressor = 50%
hence power drawn = 4.41 * 10^-4 kw * 50% = 2.20 * 10^-4 kw
Answer:
1.2727 stokes
Explanation:
specific gravity of fluid A = 1.65
Dynamic viscosity = 210 centipoise
<u>Calculate the kinematic viscosity of Fluid A </u>
First step : determine the density of fluid A
Pa = Pw * Specific gravity = 1000 * 1.65 = 1650 kg/m^3
next : convert dynamic viscosity to kg/m-s
210 centipoise = 0.21 kg/m-s
Kinetic viscosity of Fluid A = dynamic viscosity / density of fluid A
= 0.21 / 1650 = 1.2727 * 10^-4 m^2/sec
Convert to stokes = 1.2727 stokes
Explanation:
A.
H = Aeσ^4
Using the stefan Boltzmann law
When we differentiate
dH/dT = 4AeσT³
dH/dT = 4(0.15)(0.9)(5.67)(10^-8)(650)³
= 8.4085
Exact error = 8.4085x20
= 168.17
H(650) = 0.15(0.9)(5.67)(10^-8)(650)⁴
= 1366.376watts
B.
Verifying values
H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(670)⁴
= 1542.468
H(T+ΔT) = 0.15(0.9)(5.67)(10^-8)(630)⁴
= 1205.8104
Error = 1542.468-1205.8104/2
= 168.329
ΔT = 40
H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(690)⁴
= 1735.05
H(T-ΔT) = 0.15(0.9)(5.67)(10^-8)(610)⁴
= 1735.05-1059.83/2
= 675.22/2
= 337.61