Question

A household refrigerator runs one-fourth of the time and removes heat from the food compartment at an average rate of 800 kJ/h. If the COP of the refrigerator is 2.2, determine the power the refrigerator draws when running.

Answer 1

Answer:

1454.54 kJ/h or 0.404 kW

Explanation:

Given:

Removal of heat by the refrigerator = 800 kJ/h

Coefficient of performance, COP of the refrigerator = 2.2

given that the  refrigerator runs one-fourth of the time only

therefore, refrigerator removes the heat, Q = $4\times 800 kJ/h$ = 3200 kJ/h

Now, the Power drawn by the refrigerator while running = $\frac{Q}{COP}$

=  $\frac{3200 kJ/h}{2.2}$

= 1454.54 kJ/h

Hence, the power drawn by the refrigerator while running is = 1454.54 kJ/h

or 0.404 kW      (as 1 kW = 3600 kJ/h)