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Aloiza [94]
3 years ago
15

2 multiple choice questions, Please help

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

1) b. Radioactive

2. a) tevatron

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NH4OH+HCLO4<br> Total ionic
Serggg [28]

Answer:

OH^-(aq)+H^+(aq)\rightarrow H_2O(l)

Explanation:

Hello there!

In this case, according to the given reactants, it is firstly necessary to set up the complete molecular reaction:

NH_4OH(aq)+HClO_4(aq)\rightarrow NH_4ClO_4(aq)+H_2O(l)

Now, by knowing that ionic species are able to ionize, we are able to write the complete ionic equation:

NH_4^++OH^-+H^++ClO_4^-\rightarrow NH_4^++ClO_4^-+H_2O(l)

Whereas ammonium and chlorate ions are spectator ions because they remain the same on both sides of the equation. Therefore the total or net ionic equation would be:

OH^-(aq)+H^+(aq)\rightarrow H_2O(l)

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5 0
3 years ago
If you start with 4.5 moles of aluminum and 6.5 moles of copper chloride to make aluminum chloride and copper, what is the limit
Alex Ar [27]

Answer:

The limiting reagent is CuCl

Explanation:

The initial number of moles of aluminum, Al = 4.5 moles

The number of moles of copper, Cu = 6.5 moles

The given chemical reaction is presented as follows;

2Al + 3CuCl → 2AlCl₃ + 3Cu

Therefore, we have, 2 moles of aluminum combine with 3 moles of CuCl produces 2 moles of AlCl₃ and 3 moles of Cu

1 mole of Al will combine with (3/2) moles of CuCl,

Therefore, 4.5 moles of Al will combine with (4.5 × (3/2) = 6.75) 6.75 moles of CuCl

Given that the number of moles of CuCl present is only 6.5 moles which is less than the 6.75 moles required to combine with the 4.5 moles, the 6.5 moles of CuCl limits the amount of AlCl₃ and Cu produced, and therefore the CuCl is the limiting reagent.

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3 years ago
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dangina [55]

Answer:

The particles decrease & they lose energy.

Explanation:

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