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slavikrds [6]
2 years ago
12

A 975-kg sports car (including driver) crosses the rounded top of a hill (radius = 88.0 m) at 18.0 m/s. Determine (a) the normal

force exerted by the road on the car, (b) the normal force exerted by the car on the 62.0-kg driver, and (c) the car speed at which the normal force on the driver equals zero.

Physics
1 answer:
Elan Coil [88]2 years ago
6 0

Answer: a) 5965.2N b) 379.2N c) 29.37m/s

Explanation: shown in the attachment

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Six dogs pull a two-person sled with a total mass of 220 kg. The coefficient of kinetic friction between the sled and the snow i
irina [24]

Answer:

a) 2457J

b) 558W

c) 337N

Explanation:

Assuming dogs started from rest.

v=a*t\\t=\frac{a}{v}\\v=12\frac{km}{h}\frac{1000m}{km}*\frac{1h}{3600s}\\\\v=3.3m/s\\\\t=\frac{3.3m/s}{0.75m/s^2}\\t=4.4s

and the displacement is given by:

d=\frac{1}{2}*a*t^2\\d=7.3m

Using the energy conservation formula:

K_i+U_i+W_d+W_f=K_f+U_f

Because the motion started from rest the initial kinetic energy is zero, the motion occurred in-ground level so the gravitational energy is zero too.

the work done by the friction force is given by:

W_f=F_f*d*cos(\theta)\\W_f=\µ*m*g*d*cos(180)\\W_f=0.08*220kg*9.8m/s^2*7.3m*(-1)\\W_f=-1259J

so:

W_d=\frac{1}{2}*220kg*(3.3m/s)^2+1259J\\W_d=2457J

The power is given by:

P=\frac{W}{t}\\\\P=\frac{2457J}{4.4s}\\\\P=558W

and the force exerted by the dogs:

W_d=F_d*d*cos(\theta)\\F_d=\frac{W_d}{d*cos(0)}\\\\F=\frac{2457J}{7.3m*(1)}\\\\F=337N

4 0
2 years ago
What would happen if the gravitational force between the moon suddenly disappeared?
Margaret [11]
So many thinks the water wouldnt have as many waves it could result in no season and even an ice age. Nights would be darker. In result in the tides changing animals will be confused, some species rely on the tides for food and shelter. So without that it would cause a chain of mass extinction.
8 0
3 years ago
Give an example of the of conservation of momentum
seropon [69]
Refraction is the bending of a wave when it enters a medium where its speed is different. This phenomenon is explained by the conservation of energy and conservation of momentum. 

Law of Conservation of energy states the total energy of an isolated system remains constant.

law of conservation of momentum states that in a closed system the total momentum is constant.

<span>In refraction, when a medium changes, the phase velocity also changes but its frequency does not; it remains constant. </span>
3 0
2 years ago
How much work did the movers do (horizontally) pushing a 46.0-kgkg crate 10.5 mm across a rough floor without acceleration, if t
-BARSIC- [3]

Answer:

7.1 J

Explanation:

From the question,

Work done by the mover  = work done in pushing the crate + work done against friction

W = W'+Wf................. Equation 1

W = mgd+mgμd............ Equation 2

W = mgd(1+μ)................ Equation 3

Where m = mass of the crate, g = acceleration due to gravity, d = distance, μ = coefficient of  friction.

Given: m = 46 kg, d = 10.5 mm = 0.0105 m, μ = 0.5

constant: g = 9.8 m/s²

Substitute these values into equation 3

W = 46×9.8×0.0105(1+0.5)

W = 7.1 J

7 0
3 years ago
Can I have answers of all these questions?<br> Urgent plz!
Leona [35]
Q3. (a) 0m/s, as they are asking for initial velocit.
(b)(i) The paper has a large surface area or weighs less than the coin,thus,falls smoothly.
(ii)The coin has more mass than the paper.
(c) They fall at the same acceleration and hit the bottom at the same time.
Their mass doesn't matter in the vacuum.
7 0
2 years ago
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