Question

Electromagnetic radiation of 5.16Ă—1016 Hz frequency is applied on a metal surface and caused electron emission. Determine the work function of the metal if the maximum kinetic energy (Ek) of the emitted electron is 4.04Ă—10-19 J.

Answer 1

Answer:

Work function of the metal, $W_o=3.38\times 10^{-17}\ J$

Explanation:

We are given that  

Frequency of the electromagnetic radiation,  $f=5.16\times 10^{16}$ Hz

The maximum kinetic energy of the emitted electron, $K=4.04\times 10^{-19}\ J$

We need to find the work function of the metal.

We know that the maximum kinetic energy of ejected electron

$K=h\nu-w_o$

Where h=Plank's constant=$6.63\times 10^{-34} J.s$

$\nu$ =Frequency of light source

$w_o$=Work function

Substitute the values in the given formula  

Then, the work function of the metal is given by :

$W_o=h\nu -K$

$W_o=6.63\times 10^{-34}\times 5.16\times 10^{16}-4.04\times 10^{-19}$

$W_o=3.38\times 10^{-17}\ J$

So, the work function of the metal is $3.38\times 10^{-17}\ J$. Hence, this is the required solution.