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3 years ago

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Electromagnetic radiation of 5.16Ă—1016 Hz frequency is applied on a metal surface and caused electron emission. Determine the w

ork function of the metal if the maximum kinetic energy (Ek) of the emitted electron is 4.04Ă—10-19 J.

1 answer:

IgorC [24]3 years ago

8 0

Answer:

Work function of the metal, $W_o=3.38\times 10^{-17}\ J$

Explanation:

We are given that

Frequency of the electromagnetic radiation, $f=5.16\times 10^{16}$ Hz

The maximum kinetic energy of the emitted electron, $K=4.04\times 10^{-19}\ J$

We need to find the work function of the metal.

We know that the maximum kinetic energy of ejected electron

$K=h\nu-w_o$

Where h=Plank's constant= $6.63\times 10^{-34} J.s$

$\nu$ =Frequency of light source

$w_o$ =Work function

Substitute the values in the given formula

Then, the work function of the metal is given by :

$W_o=h\nu -K$

$W_o=6.63\times 10^{-34}\times 5.16\times 10^{16}-4.04\times 10^{-19}$

$W_o=3.38\times 10^{-17}\ J$

So, the work function of the metal is $3.38\times 10^{-17}\ J$ . Hence, this is the required solution.

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A horizontal pipe of diameter 1.03m has a smooth constriction to a section of diameter 0.618 m. The density of oil flowing in th

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