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LekaFEV [45]
3 years ago
5

The force that moves fluid out of capillaries is ________ pressure whereas the opposing force that moves fluid into capillaries

is ________ pressure. plasma; extracellular systolic; diastolic blood; interstitial colloid osmotic; hydrostatic hydrostatic; colloid osmotic
Physics
1 answer:
konstantin123 [22]3 years ago
3 0

Answer:

<u><em>hydrostatic</em></u><em>; </em><u><em>colloid osmotic</em></u>

Explanation:

Hydrostatic pressure, <em>due to the force of gravity, is the pressure exerted by a liquid at an equilibrium point inside the fluid. </em>

Due to the increasing weight of the water exerting downward force from above, hydrostatic pressure increases in proportion to the distance measured from the surface.

Oncotic pressure, or colloid osmotic pressure, i<em>s a type of protein-induced osmotic pressure, especially albumin, in the plasma (blood / liquid) of a blood vessel which displaces water molecules, causing a relative molecular water deficit with water molecules moving back into the circulatory system within the capillary end of the lower venous pressure.</em>

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Consider the waves on a vibrating guitar string and the sound waves the guitar produces in the surrounding air. The string waves
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Answer:

Frequency is the correct answer.

Explanation:

When a wave go from one medium to another medium then the velocity, wavelength and Amplitude changes. But there is no change on the frequency.

Here, The string and the surroundings air are two medium , from which the wave travels.

So, the wave has same frequency in both medium.

The correct answer is Frequency.

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What is the difference between pitch and volume?
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A) A spaceship passes you at a speed of 0.800c. You measure its length to be 31.2 m .How long would it be when at rest?
rosijanka [135]

Answer:

a

     l_o  =52 \  m

b

      l = 37.13 \ LY

Explanation:

From the question we are told that

    The  speed of the spaceship is  v  =  0.800c

    Here  c is the speed of light with value  c =  3.0*10^{8} \ m/s

    The  length is  l = 31.2 \  m

     The  distance of the star for earth is d = 145 \  light \  years

     The  speed is v_s = 2.90 *10^{8}

     

Generally the from the length contraction equation we have that

       l  =  l_o  \sqrt{1 -[\frac{v}{c } ]}

Now the when at rest the length is  l_o

So  

      l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }

      l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }

      l_o=52 \  m

Considering b  

  Applying above equation

            l  =l_o \sqrt{1 -  [\frac{v}{c } ]}

Here l_o  =145 \  LY(light \ years )

So

           l=145 *  \sqrt{1 -  \frac{v_s^2}{c^2 } }

            l =145 *  \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }

            l = 37.13 \ LY

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3 years ago
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