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Sophie [7]
3 years ago
5

Describe the photoelectric effect and explain why it made modifications to the Rutherford model necessary.

Chemistry
2 answers:
avanturin [10]3 years ago
7 0

Photoelectric effect refer to the emission of electron or free carriers when light shine into a material. According to the Rutherford model, light of any energy should be able to make electrons leave the atom and be emitted. The energy of the emitted electrons should be related to the intensity of the light. But the energy of the electron is actually only related to the energy of the light



Furkat [3]3 years ago
6 0
<span>Photoelectric effect refer to the emission of electron or free carriers when light shine into a material. According to the Rutherford model, light of any energy should be able to make electrons leave the atom and be emitted. The energy of the emitted electrons should be related to the intensity of the light. But the energy of the electron is actually only related to the energy of the light</span>
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What is formed when the number of electrons is changed?
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Answer:

Explanation:

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3 years ago
A chemist requires 5.00 liters of 0.420 M H2SO4 solution. How many grams of H2SO4 should the chemist dissolve in water? 129 gram
natali 33 [55]

Answer:

Approximately 206 grams.

Explanation:

How many moles of sulfuric acid \mathrm{H_2SO_4} are there in this solution?

\text{Number of moles of solute} = \text{Concentration} \times \text{Volume}.

The unit for concentration "\mathrm{M}" is equivalent to mole per liter. In other words, \rm 1\;M = 1\; mol\cdot L^{-1}. For this solution, the concentration of \mathrm{H_2SO_4} is \rm 0.420\;M = 0.420\; mol\cdot L^{-1}.

\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V\\&= \rm 0.420\;mol\cdot L^{-1}\times 5.00\; L \\&= \rm 2.10\; mol\end{aligned}.

What's the mass of that \rm 2.10\; mol of \mathrm{H_2SO_4}?

Start by finding the molar mass M of \mathrm{H_2SO_4}.

Relative atomic mass data from a modern periodic table:

  • H: 1.008;
  • S: 32.06;
  • O: 15.999.

\displaystyle M(\mathrm{H_2SO_4}) = 2\times \underbrace{1.008}_{\mathrm{H}} + 1\times \underbrace{32.06}_{\mathrm{S}} + 4\times \underbrace{15.999}_{\mathrm{O}} = \rm 98.072\;g\cdot mol^{-1}.

\text{Mass} = \text{Quantity in moles} \times \text{Molar Mass}.

m = n \cdot M = \rm 2.10\; mol \times 98.072\;g\cdot mol^{-1} \approx 206\; g.

In other words, the chemist shall need approximately 206 grams of \mathrm{H_2SO_4} to make this solution. As a side note, keep in mind that the 206 grams of \mathrm{H_2SO_4} also take up considerable amount of space. Therefore it will take less than 5.00 L of water to make the 5.00 L solution.

6 0
4 years ago
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Explanation: I hope that helped

8 0
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