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dybincka [34]
3 years ago
15

PLEASE HURRY!

Physics
2 answers:
Sever21 [200]3 years ago
8 0

Answer:

3

Explanation:

AlexFokin [52]3 years ago
4 0

Answer:

Section: 4–1 Topic: Newton's First Law: The Law of Inertia Type: Conceptual ... B) whether an object is at rest or is moving with constant velocity depends on the ... E) The acceleration of a body is proportional to the net external force acting on it ... The position vector at t = 2 s is. A) jm im r ˆ0.5ˆ0.1. +. = D) jm im r. ˆ0.10ˆ0.2. +.

Explanation:

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3 years ago
A force on a particle depends on position such that F(x) = (3.00 N/m2)x2 + (6.00 N/m)x for a particle constrained to move along
Pachacha [2.7K]

Answer:

The work done by a particle from x = 0 to x = 2 m is 20 J.

Explanation:

A force on a particle depends on position constrained to move along the x-axis, is given by,

F(x)=(3\ N/m^2)x^2+(6\ N/m)x

We need to find the work done on a particle that moves from x = 0.00 m to x = 2.00 m.

We know that the work done by a particle is given by the formula as follows :

W=\int\limits {F{\cdot} dx}

W=\int\limits^2_0 {(3x^2+6x){\cdot} dx} \\\\W={(x^3}+3x^2)_0^2\\\\\W={(2^3}+3(2)^2)\\\\W=20\ J

So, the work done by a particle from x = 0 to x = 2 m is 20 J. Hence, this is the required solution.

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When drinking at a private even, you should assume that drinks will ___.
allochka39001 [22]

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