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SSSSS [86.1K]
3 years ago
14

The clear, yellowish liquid that is seen after a clot forms is called ____________________.

Chemistry
1 answer:
RSB [31]3 years ago
4 0
Serum...

hope it helps
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The purpose of selective breeding is to
Ira Lisetskai [31]

Answer:

The purpose of selective breeding is to develop livestock whose desirable traits have strong heritable components and can therefore be propagated

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3 years ago
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Which of these lists bodies in order, from CLOSEST to FURTHEST from the Earth? A) moon, sun, near edge of milky way, center of m
marta [7]
A) would be correct.

The moon is right next to Earth.

Earth orbits around the sun.

Our solar system is at the edge of the Milky Way. So the edge of the Milky Way would be nearer than the center.
8 0
4 years ago
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What is the mass of 6.12 moles of arsenic (As)?
Leokris [45]

Mole = Mass / Molar mass

6.12 moles = Mass / 74.92 g/mol

Mass = 6.12 moles x 74.92 g/mol

Mass = 458.51g

7 0
3 years ago
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To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is diluted to 0.500 L. Analysis of the dilute
julia-pushkina [17]

Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molar concentration of undiluted cognac = ?

M_2 = molar concentration of diluted cognac = 0.0844 M

V_1 =  volume of undiluted cognac = 5.00 mL = 0.005 L

V_2 = volume of diluted cognac = 0.500 L

Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.

M_1\times 0.005L=0.0844M\times 0.500L

M_1=8.44M

Therefore, the molar concentration of ethanol in the undiluted cognac is 8.44 M

4 0
4 years ago
What is the pH of an aqueous solution of 1 M CH3COOH (pKa=4)
Mrac [35]

Answer:

pH = 2.

Explanation:

A weak acid is in equilibrium with its ions in a solution, so it must have an equilibrium constant (Ka). And, pKa = -logKa

Ka = 10^{-pKa}

Ka = 10⁻⁴

So, for CH₃COOH the equilibrium must be:

CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)

1 M                           0                0                Initial

-x                              +x              +x               Reacted

1-x                             x                x                 Equilibrium

And the equilibrium constant:

Ka = \frac{[H+]x[CH3COO-]}{[CH3COOH]}

10^{-4} = \frac{x^2}{1-x}

Supposing x << 1:

10⁻⁴ = x²

x = √10⁻⁴

x = 10⁻² M, so the supposing is correct.

So,

pH = -log[H⁺]

pH = -log10⁻²

pH = 2

8 0
4 years ago
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