The ratio of the rotational kinetic energy about the center of the sphere and the total kinetic energy of the sphere is 2/7.
<h3>What is the
rotational kinetic energy of a sphere?</h3>
The rotational kinetic energy of the sphere is directly proportional to the square of angular acceleration.
Where,
= rotational inertia of sphere = 2/5MR²
Where 
is the mass of the sphere and 
is the radius of the sphere,
ω = angular acceleration of sphere = V/R
Where 
is the speed of the sphere.
So,
K = 1/2 × 2/5MR² × V²/R²
K = MV²/5
The translational kinetic energy of the sphere,
The total kinetic energy of the sphere,
So,
Thus the Ratio of rotational kinetic energy to total kinetic energy,
Therefore, the ratio of the rotational kinetic energy about the center of the sphere and the total kinetic energy of the sphere is 2/7.
Learn more about rotational kinetic energy:
brainly.com/question/14611300
Answer:
16.732 N
Explanation:
Given:
q1 = 0.00047 C = 4.7 x 10^-4 C
q2 = 0.00089 C = 8.9 x 10^-4 C
d = 15 m
k = 9 x 10^9 N m^2 / C^2
To Find:
F = ?
Solution:
F = k x q1 x q2/d^2
F = 9 x 10^9 x 4.7 x 10^-4 x 8.9 x 10^-4 / 15 x 15
F = 9 x 4.7 x 8.9 x 10^9 x 10^-4 x 10^-4 / 225
F = 9 x 4.7 x 8.9 x 10^9 x 10^-8 / 225
F = 9 x 4.7 x 8.9 x 10 / 225
F = 418.3/25
F = 1673.2/100
Therefore, F = 16.732 N
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Answer:
effective ground-fault current path
Explanation:
"decreasing the distance of the space shuttle from Earth"
F = Gm(1)m(2)/R²
where R is the distance between the 2 objects, as it decreases, the force increases.
Answer:
THE ANSWER TERMS ARE DEFINED BLOW:-
Explanation:
MOMENTUM- IT IS THE ABILITY TO INCREASE OR DEVELOP CONSTANT FORCE.
KINETIC ENERGY:- IT IS THE ENERGY THAT A PRTICLE POSSES WHEN IT IS ACTUALLY IN MOTION.
POTENTIAL ENERGY:- IT IS THE ENERGY THAT A PARTICLE POSSES WHEN IT ACTUALLY IS IN RESTING STATE.
IN THIS ACIVITY THE SNOWBOARDER IS IN THE MOTION STATE THEREFORE HE POSSES KINETIC ENERGY AND TO MAINTAIN THAT KINEITC ENERG FOR A PERIOD OF TIME,MOMENTUM PLAYS IT'S ROLE.
