The Lewis structure of Carbonic Acid (H₂CO₃) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with hydroxyl groups.
Formal Charge; Formal charge is caculated as,
Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]
Formal charge on Carbon;Formal charge = 4 - [ 0 + 8/2]
Formal charge = 4 - [4]
Formal charge = Zero
Answer:
102.807 kPa
Explanation:
There are some assumptions to be made in the answer. The air inside the balloon acts as an ideal gas at a given temperature conditions.
Using the combined ideal gas equation.
P= absolute pressure of air inside the balloon.
V= volume of air inside the balloon (6.23 L= 6.23 * 10⁻³ m³)
n= moles of gas(air). (0.250 mol)
R= Universal gas constant ( 8.314 J / mol·K)
T= Temperature in Kelvin
T= 35 + 273.15 = 308.15 K
So, 
P= 102.807 * 10³ Pa
P= 102.807 kPa
There are 3 significant digits in 5.40.
(To help understand): Sig figs are just a way of simplifying a number.
Answer:
HCO3- + BrO- → HBrO + CO32-
Explanation:
I think this is the answer hope it helps
We need draw the structure of (3E,5E)-2,5-dibromo-3,5-octadiene.
The structure is shown below:
The molecule has two double bonds in 3 and 5 position and two Br-atoms attached to 2 and 5 position.
The configuration is 3E and 5E. E configuration indicates cis- isomers where similar groups are in same side with respect to double bonds.
