Answer:
140.83 W
Explanation:
From the question given above, the following data were obtained:
Height (h) = 26 m
Time (t) = 12 s
Mass (m) = 6.50 Kg
Power (P) =?
Power is simply defined as the rate at which energy is used up. Mathematically, it is expressed as:
Power (P) = Energy (E) / Time (t)
But:
Energy (E) = mass (m) × acceleration due to gravity (g) × height (h)
E = mgh
P = E/t
P = mgh / t
With the above formula i.e
P = mgh / t
We can obtain the power supplied by Jill's muscles as follow:
Height (h) = 26 m
Time (t) = 12 s
Mass (m) = 6.50 Kg
Acceleration due to gravity (g) = 10 m/s²
Power (P) =?
P = mgh / t
P = 6.5 × 10 × 26 / 12
P = 140.83 W
Therefore, the power supplied by Jill's muscles is 140.83 W
Answer:
When the metal is dropped in the solution it turns blue to green because this forms iron sulphate solution and turns the metal copper
Iron sulphate + copper
Answer:
Positive
Explanation:
Work is defined as the product of displacement of an object produced by the applied force and the component of force along that direction. Let us consider a situation in which the angle between the applied force and the displacement produced by it is at an angle θ. Let the magnitude of displacement be s and that of the applied force be F. Now, we have to find the component of force along the direction of the displacement. For that we have to resolve the force in to two components- one along the direction of displacement and other perpendicular to it. Since the angle between force and displacement is θ, the component of force along the direction of displacement will be Fcosθ and that perpendicular to it will be Fsinθ. Thus, b the definition of work, work done = Fcosθ x s = Fscosθ.
Now, coming to our question, the force here is gravitational force of attraction which is along downward direction. It is given in the question itself that the stone is falling down. Since the displacement and the applied force is along the same direction, angle between them, θ = 0.
Thus, work done = Fscosθ = Fscos0 = Fs (since cos0 =1)
Fs > 0
Thus, the work done is positive
To solve this problem we will apply the concepts related to classical mechanics, for which we will first consider the general equation that describes the movement of the body. From there, as we well know, we will obtain the derivative, which is equivalent to the speed of the body and the rate of change that is investigated in the problem.
Our values are given as,
We will start by defining the general height 'y' of the body at a reference distance of the lifting copter, given as
Differentiating both the sides we have
Now when the altitude of the copter is 124ft we have that
And,
Using these values at the derivative equation finally we have that
Therefore the distance between the man and the helicopter is increasing at the rate of 40.68ft/s
Answer:
i would think it is to the left
Explanation:
the normal and gravitational forces cancel each other out so the only force left is the one to the left
the only thing that throws me off is it says friction
hope this is right and helps