Answer:
low powered radio frequency (RF) energy
A Correcting each car to the same size as the first one invented could get in the way during work days.
Answer:
a)
b)
Explanation:
We start the exercise knowing that a ball is thrown up with an initial velocity of 65 ft/s with an initial height of 680 ft.
To calculate the maximum heigh, we know that at the top of the motion the ball stop going up and start going down because of the <em>gravity</em>
First of all, we need to calculate the time that takes the ball to reach the maximum point.
a)
Knowing that time, <u><em>we can calculate the height to which the ball rises:</em></u>
b) Now, to know the time that the ball reach the bottom of the cliff, we know that the final height is y=0ft
This is a classic quadratic equation, that can be solve using the quadratic formula
a=-16.1
b=65
c=640
Solving for t, we have that
or
Since the time can not be negative:
Answer:
Distance = 3.69 × 10^9 m
The distance from the probe to Earth is 3.69 × 10^9 m
Explanation:
Distance from the probe to the Earth can be derived using the simple motion formula;
Distance = speed × time .....1
Since a radio signal uses an electromagnetic wave to transfer signal, it has the same speed as the speed of light.
Speed of radio signal = speed of light = 3.0 × 10^8 m/s
time taken to reach the earth = 12.3 seconds
Substituting the values of speed and time into equation 1;
Distance = 3.0 × 10^8 m/s × 12.3 s
Distance = 36.9 × 10^8 m
Distance = 3.69 × 10^9 m
Note: all electromagnetic radiation have the same speed which is equal to 3.0 × 10^8 m/s
Answer:
a) , b) , c) ,
Explanation:
a) The angular motion is obtained by integrating the angular acceleration function twice:
The angular motion when t = 2 s. is:
b) Let be the distance between A and the rotation axis, measured in meters. The magnitude of the angular velocity when t = 2 s. is:
Finally, the magnitude of the velocity is:
c) The angular acceleration of the disk when t = 2 s. is:
Lastly, the normal and tangential components at point A are, respectively: