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Anton [14]
3 years ago
9

Calculate the number of moles of Californium represented by 5.92 x 1024 atoms of Californium. Enter your answer in the provided

box. mol Cf
Chemistry
1 answer:
Fed [463]3 years ago
8 0

Answer:

9.834 moles Cf.

Explanation:

The number of moles of a substance is an easy way to represents its amount. Avogadro has determined that the total amount in 1 mol is equal to 6.02x10²³(Avgadros' number), so 1 mol has 6.02x10²³ atoms, molecules, ions, or what we are measuring. So:

1 mol of Cf -------------------- 6.02x10²³ atoms

x -------------------- 5.92x10²⁴

By a simple direct three rule:

6.02x10²³x = 5.92x10²⁴

x = 5.92x10²⁴/6.02x10²³

x = 9.834 moles Cf

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How many grams of water can be produced in the combination of
mel-nik [20]

If 14 grams of hydrogen reacted with 24.7 grams of oxygen 27.7875 grams of water will be formed.

Explanation:

2H2+O2----------->2H2O.

  • From the above equation, we can say that 4g of Hydrogen will react with 32 g of oxygen.
  • In this question, Hydrogen is in excess amount.
  • 32 g of Oxygen will react with = 4 g of H2.
  • Therefore 24.7g of Oxygen will react with =24.7x4/32= 3.0875 g H2.  
  • The remaining 10.9125g of H2 will be left unreacted.
  • Therefore the amount of water formed=(24.7+3.0875)=27.7875 g

7 0
3 years ago
List the substances Ar, Cl2, CH4, and CH3COOH, in order of increasing strength of intermolecular attractions. List the substance
Viefleur [7K]

Answer:

Order of increasing strength of intermolecular attraction:

CH_3COOH > Cl_2 > CH_4 > Ar

Explanation:

CH_3COOH can form hydrogen bond as H atom is attached with electronegative atom O.

Rest three, Cl_2,  CH_4,  Ar are non-polar molecules.

In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, CH_3COOH has strongest intermolecular attractions.

Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.

Molecular size and mass of Cl_2 is high as compared to CH_4.

van der Waals intermolecular forces of attraction increases with increase in size.

Therefore,

Order of increasing strength of intermolecular attraction will be:

CH_3COOH > Cl_2 > CH_4 > Ar

8 0
3 years ago
Read 2 more answers
b) Si los ácidos nitroso y fluorhídrico están descritos como electrolitos débiles, ¿significa que en la disolución hay moléculas
viva [34]

Los electrolitos son sustancias que se disocian en agua para dar iones.

Generalmente en química, podemos clasificar sustancias como

  • Electrolitos
  • No electrolitos

Los electrolitos pueden disociarse en solución para producir iones, pero un no electrolito no puede hacer eso.

Entre los electrolitos hay dos clases;

  • Electrolitos fuertes
  • Electrolitos débiles

Los electrolitos fuertes se disocian completamente en solución, mientras que los electrolitos débiles no se disocian completamente en solución.

El hecho de que los electrolitos débiles no se disocien por completo significa que algunas moléculas de la sustancia no se disocian.

Por lo tanto, si los ácidos nitroso y fluorhídrico se describen como electrolitos débiles, esto significa que hay moléculas en la solución que no están disociadas.

Lea más: brainly.com/question/14566383

5 0
2 years ago
Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H2S(g) 3O2(g)2H2O(l) 2SO2
Marizza181 [45]

Answer:

\Delta _rH=-1124.14kJ/mol

Explanation:

Hello!

In this case, since the standard enthalpy change for a chemical reaction is stood for the enthalpy of reaction, for the given reaction:

2H_2S(g) +3O_2(g)\rightarrow 2H_2O(l) +2SO_2(g)

We set up the enthalpy of reaction considering the enthalpy of formation of each species in the reaction at the specified phase and the stoichiometric coefficient:

\Delta _rH=2\Delta _fH_{H_2O,liq}+2\Delta _fH_{SO_2,gas}-2\Delta _fH_{H_2S,gas}-3\Delta _fH_{O_2,gas}

In such a way, by using the NIST database, we find that:

\Delta _fH_{H_2O, liq}=-285.83kJ/mol\\\\\Delta _fH_{SO_2, gas}=-296.84kJ/mol\\\\\Delta _fH_{O_2,gas}=0kJ/mol\\\\\Delta _fH_{H_2S,gas}=-20.50kJ/mol

Thus, we plug in the enthalpies of formation to obtain:

\Delta _rH=2(-285.73kJ/mol)+2(-296.84kJ/mol)-2(-20.50kJ/mol)-3(0kJ/mol)\\\\\Delta _rH=-1124.14kJ/mol

Best regards!

8 0
2 years ago
Which of these solids is insoluble in water?
eimsori [14]
The answer would be A) sand, it is not soluble in water
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