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Phoenix [80]
4 years ago
7

NEED HELP A 25.0 mL solution of nitric acid (HNO3) with an unknown concentration is titrated with 12.5 mL of a 1.0x10-4 M soluti

on of lithium hydroxide (LiOH). Calculate the molar concentration of the HNO3.
3.80x10-10 M HNO3

5.00x10-5 M HNO3

2.80x10-3 M HNO3

2.30x10-5 M HNO3

2.50x10-5 M HNO3
Chemistry
1 answer:
dimulka [17.4K]4 years ago
3 0

Answer:

The concentration of HNO3 is 5*10^-5 M (option 2)

Explanation:

Step 1: Data given

Volume of HNO3 solution = 25.0 mL

Volume of 1*10^-4 M LiOH solution = 12.5 mL

Step 2: The balanced equation

HNO3 + LiOH → LINO3 + H2O

Step 3: Calculate the molar concentration of the HNO3.

b*Ca*Va = a*Cb*Vb

→ with Ca = the concentration of HNO3 = TO BE DETERMINED

→ with Va = the volume of HNO3 = 25.0 mL = 0.025 L

→ with Cb = the concentration of LiOH = 1.0 * 10^-4 M

→ with Vb = the volume of 12.5 mL = 0.0125 L

→ with a = the coefficient of HNO3 = 1

→ with b = the coefficient of LiOH = 1

1*Ca*0.025 L = 1 * 1*10^-4 * 0.0125 L

Ca = 0.00005M =5*10^-5 M

The concentration of HNO3 is 5*10^-5 M (option 2)

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