1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir [108]
3 years ago
15

A teacher is demonstrating energy transformation with a basketball. He drops the ball from a fixed height and challenges his stu

dents to predict the height that the ball will bounce. • Student A predicts that the ball will bounce to the exact height it was dropped. • Student B predicts that the ball will bounce at a height lower than the height it was dropped. What is a reasonable rationale for the predictions of student A and student B? Be sure to include an explanation of the energy transformation as well.
Physics
1 answer:
Luda [366]3 years ago
5 0

The ball will bounce at a height lower than the height it was dropped.

Answer: Option B.

<u>Explanation:</u>

When a basket ball is thrown from a particular height, it bounces back. But the height it bounces back at is not exactly the same height from where it was thrown.

With further bounces, the energy of the basket ball goes on decreasing and the bounces go on getting smaller. This shows that there is a change in the energy of the basket ball with every bounce that the ball makes. Some energy lost from the ball gets absorbed by the court and some of the energy is changed into thermal energy.

You might be interested in
The acceleration vector of a particle in projectile motion ________.
Alex73 [517]

Answer:

Points downward, and its magnitude is 9.8 m/s^2

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform horizontal motion, with constant velocity and zero acceleration. In fact, there are no forces acting on the projectile along the horizontal direction (if we neglect air resistance), so the acceleration along this direction is zero.

- A vertical motion, with constant acceleration g = 9.8 m/s^2 towards the ground (downward), due to the presence of gravity wich "pulls" the projectile downward.

The total acceleration of the projectile is given by the resultant of the horizontal and vertical components of the acceleration. But we said that the horizontal component is zero, therefore the total acceleration corresponds just to its vertical component, therefore it is a vector with magnitude 9.8 m/s^2 which points downward.

4 0
3 years ago
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan
Nesterboy [21]

Answer:

Compression distance: d \approx 0.102\,m

Explanation:

According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy (K), in joules, at the expense of elastic potential energy (U), in joules, and overcoming work losses due to friction (W_{l}), in joules:

K + W_{l} = U (1)

By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2} (2)

Where:

m - Mass of the block, in kilograms.

v - Final velocity of the block, in meters per second.

\mu - KInetic coefficient of friction, no unit.

g - Gravitational acceleration, in meters per square second.

s - Width of the rough patch, in meters.

k - Spring constant, in newtons per meter.

d - Compression distance, in meters.

If we know that m = 1.2\,kg, v = 2.3\,\frac{m}{s}, \mu = 0.44, g = 9.807\,\frac{m}{s^{2}}, s = 0.05\,m and k = 730\,\frac{N}{m}, then the compression distance of the spring is:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2}

m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}

d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }

d \approx 0.102\,m

4 0
3 years ago
The diagram illustrates the movement of sound waves between an observer and a race car. As the race car drives away from the obs
Andrei [34K]
I believe the answer is d
6 0
4 years ago
The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g o
satela [25.4K]

Answer:

Q = 50.25 [J]

Explanation:

To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.

Q = m*Cp*(DT)

where:

Q = energy in form of heat [J]

m = mass = 5 [g] = 0.005 [kg]

Cp = specific heat = 1005 [J/kg*°C]

DT = temperature change = 10 [°C]

Now replacing:

Q = 0.005*1005*10

Q = 50.25 [J]

4 0
4 years ago
Help please asap I'm super lost
vaieri [72.5K]
A compound is two or more elements combinded together.
A element is a pure substance.
it looks like all of them are compounds except the carbon dixode, My teacher would accept that as a anwser idk bout urs thoughs.
6 0
3 years ago
Read 2 more answers
Other questions:
  • If one star has a temperature of 5200 K and another star has a temperature of 7900 K, how much more energy per second will the h
    10·1 answer
  • Big bang theorists believe that the universe is expanding and will eventually contract.
    8·1 answer
  • Apply Newton's first law of motion to a sprinter in a race.
    5·1 answer
  • Help me plz I don't understand my science hw
    13·1 answer
  • While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the
    5·2 answers
  • What force pulled the leaf to the ground
    7·1 answer
  • In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.18 m. The mug
    7·1 answer
  • A 0.20 kg particle moves along the x axis under the influence of a stationary object. The potential energy is given by U(x) = 8x
    13·1 answer
  • PART 2
    7·2 answers
  • The field found in this problem for a moving charge is the same as the field from a current element of length dl carrying curren
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!