Question

If I fill a balloon with 5.2 moles of gas and it creates a balloon with a volume of 23.5 liters, how many moles are in a balloon at the same temperature and pressure that has a volume of 14.9 liters?

Answer 1

Answer:

When the volume reduces to 14.9 L, the number of moles decreases to 3.3 moles of gas

Explanation:

Step 1: Data given

Number of moles gas = 5.2 moles

Volume = 23.5 L

Volume reduced to 14.9 L

Step 2: Calculate the new amount of moles

V1/n1 = V2/n2

⇒with V1 = the initial volume of the gas = 23.5 L

⇒with n1 = the initial number of moles gas = 5.2 moles

⇒with V2 = the reduced volume = 14.9 L

⇒with n2 = the new amount of moles gas = TO BE DETERMINED

23.5 L/ 5.2 moles = 14.9 L / n2

n2 = 14.9 L (23.5 L / 5.2 moles)

n2 = 3.3 moles

When the volume reduces to 14.9 L, the number of moles decreases to 3.3 moles of gas

Answer 2

Answer:

n= 0.303mol

Explanation:

From PV= nRT

R= PV/nT

Comparing 2-systems of baloons

P1V1/n1T1 = P2V2/n2T2

Since pressure and temperature are constant

V1/n1= V2/n2

23.5/5.2 = 14.9/n2

Simplify

n2= 0.303mol