Answer:
77.14 atm of pressure should be of an acetylene in the tank.
Explanation:
According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.
Moles of oxygen=
Moles of acetylene =
Volume of large tank with oxygen gas,
Pressure of the oxygen gas inside the tank =
..[1]
Volume of small tank with acetylene gas ,
Pressure of the acetylene gas inside the tank =
..[2]
Considering both the gases having same temperature T, [1]=[2]
77.14 atm of pressure should be of an acetylene in the tank.
Answer:
The answer is c radio --> infrared --> ultraviolet --> gamma
Explanation:
I just did it
Answer: 0.75
Explanation:
Mathematically, the equilibrium constant Keq is the concentration of product divided by the concentration of the reactant.
And since the product is fructose 6-phosphate (F6P) while the reactant is glucose 6-phosphate (G6P):
Keq = [F6P] / [G6P]
Keq = 0.6 / 0.8
Keq = 0.75 (since Keq is almost equal to 1, it means the amount of F6P and G6P in the reaction is almost the same)
Thus, the equilibrium constant Keq for this reaction is 0.75