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Leni [432]
3 years ago
14

In the biosynthetic pathway for folic acid, the compound PABA is the normal substrate for an enzyme in the pathway. The antibiot

ic sulfanilamide is very similar in structure to PABA and will act as a(n) _______ of the enzyme that acts on PABA.
Chemistry
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

Inhibitor

Explanation:

Enzyme inhibitors are compounds that can interact with the enzyme but don't trigger any biological response. This is what sulfanilamide does. When the enzyme is bound to sulfanilamide, it stops being able to bind PABA, its normal substrate, and so it cannot perform its biological action. In consequence, the entire biosynthetic pathway for folic acid is stopped.

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What is the name of Pb(NO3)2? Explain how you determined the bond type and the steps you used to determine the naming convention
Elena L [17]

Answer: Lead(II) nitrate but idk the rest

Explanation:

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3 years ago
Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo
Luda [366]

Answer:

0.800 mol of O2

Explanation:

<em>Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.</em>

The balanced equation for the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2  

From the reaction;

6 mol of CO2 produces 6 mol of O2

0.0800 mol of CO2 would produce x mol of O2

6 = 6

0.0800 = x

Solving for x;

x = 6 * 0.800 / 6

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2 years ago
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the endangered spices act

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8 0
3 years ago
A flashlight battery is hooked to a toy motor, and then the battery and the connections are sprayed with a water-proof coating.
denis-greek [22]

Explanation:

Formula to calculate work done by motor is as follows.

         Work done by motor = mass \times g \times height

where,   g = gravitational constant = 10 m/s^{2}

Therefore, work done by motor is as follows.

 Work done by motor = 1.00 kg \times 10 m/s^{2} \times 10.0 m  

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Now, heat lost by water will be calculated as follows.

            q = mC \times \Delta T

                = g \times 4.184 J/g^{o}C \times 0.024^{o}C

                = 10.0 J

Hence, heat gained by motor = heat lost by water

As, heat gained by motor = 10.0 J

So, change in energy = heat gained - work done

Therefore, change in energy will be calculated as follows.  

   Change in energy = heat gained - work done

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                                   = -90.0 J

Thus, we can conclude that change in the energy of the battery contents is -90.0 J.

4 0
3 years ago
When 50 ml of 1.000x10^-1m pb(no3)2 solution was added to 50 ml of 1.000x10^-1m nai solution?
podryga [215]

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c(Pb(NO₃)₂) = 0.1 mol/L; concentration of solution.

n(Pb(NO₃)₂) = c(Pb(NO₃)₂) · V(Pb(NO₃)₂).

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From chemical reaction: n(Pb(NO₃)₂) : n(NaI) = 1 : 2.

n(Pb(NO₃)₂) = 0.005 mol ÷ 2.

n(Pb(NO₃)₂) = 0.0025 mol; number of moles Pb(NO₃)₂ used.

n(NaI) = 0.005 mol; number of moles NaI used.

The limiting reagent is Pb(NO₃)₂.

n(PbI₂) = 0.005 mol.

m(PbI₂) = n(PbI₂) · M(PbI₂).

m(PbI₂) = 0.005 mol · 461 g/mol.

m(PbI₂) = 2.305 g; the theoretical yield of PbI₂.

3 0
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