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Leni [432]
3 years ago
14

In the biosynthetic pathway for folic acid, the compound PABA is the normal substrate for an enzyme in the pathway. The antibiot

ic sulfanilamide is very similar in structure to PABA and will act as a(n) _______ of the enzyme that acts on PABA.
Chemistry
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

Inhibitor

Explanation:

Enzyme inhibitors are compounds that can interact with the enzyme but don't trigger any biological response. This is what sulfanilamide does. When the enzyme is bound to sulfanilamide, it stops being able to bind PABA, its normal substrate, and so it cannot perform its biological action. In consequence, the entire biosynthetic pathway for folic acid is stopped.

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The rate constant for a certain reaction is k = 6.50×10−3 s−1 . If the initial reactant concentration was 0.600 M, what will the
Kamila [148]

Answer: 1.037M

Explanation:

Since the rate constant unit is per seconds, therefore it is a first order reaction.

First order reaction equation is given as

InA= -kt +InAo

Where,Ao is the initial concentration of reactant =0.600M

A is the concentration of reactant at a specifies time t=3×60=180s

and k is the rate constant

InA = -6.50×10^-3 ×180 +In(0.6)

InA = -1.17 + 0.5108

InA= -1.680

A = e-1.680

A= 1.037M

Therefore the concentration after 3minutes is 1.037M

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3 years ago
A closed circle with short lines inside on a topographical map
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That would be a depression..
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A seashell, composed largely of calcium carbonate, is placed in a solution of HCl. As a result, 1700 mL of dry CO2 gas at STP is
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Explanation:

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3 years ago
What are the missing coefficients for the skeleton equation below? Cr(s)+Fe(NO3)2(aq)>Fe(s)+Cr(NO3)3(aq)
Stolb23 [73]

Answer:

2 Cr(s) + 3 Fe(NO3)2(aq) = 3 Fe(s) + 2 Cr(NO3)3(aq)

Explanation:

I balanced this chemical equation so that both sides are equal, meaning that the mass of reactants is equal to mass of products.

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Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
2 years ago
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