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valkas [14]
3 years ago
11

A rock of mass m is thrown straight up into the air with initial speed |v0 | and initial position y = 0 and it rises up to a max

imum height of y = h. A second rock with mass 2m (twice the mass of the original) is thrown straight up with an initial speed of 2|v0 |. What maximum height does the second rock reach?
Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

Explanation:

Case 1:

mass = m

initial velocity = vo

final velocity = 0

height = y

Use third equation of motion

v² = u² - 2as

0 = vo² - 2 g y

y = vo² / 2g       ... (1)

Case 2:

mass = 2m

initial velocity = 2vo

final velocity = 0

height = y '

Use third equation of motion

v² = u² - 2as

0 = 4vo² - 2 g y'

y ' = 4vo² / 2g

y' = 4 y

Thus, the second rock reaches the 4 times the distance traveled by the first rock.

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Answer:

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2 years ago
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What is the best definition for work?
olga55 [171]

Work is done when a force is in the same direction as the object moves.

Explanation:

The work done by a force in moving an object is given by the equation

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the directions of F and d

From the equation, we notice the following:

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  • When the force is perpendicular to the motion of the object, \theta=90^{\circ} and cos \theta = 0, which means that no work done
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Therefore, the correct answer is

Work is done when a force is in the same direction as the object moves.

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brainly.com/question/6763771

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Answer:

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A cart starts from rest and accelerates at 4.0 m/s2 for 5.0 s, then maintains that velocity for 10 s, and then decelerates at th
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Answer:

Final speed of car = 12 m/s

Explanation:

We have equation of motion v = u + at, where v is final velocity, u is initial velocity, a is acceleration and t is time.

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b) Then maintains that velocity for 10 s

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