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anygoal [31]
3 years ago
11

Calculate the amounts requested if 3.30 mol Fe2O3 completely react according to the following equation. Fe2O3 + 2Al --> 2Fe +

Al2O3 <br />
a. moles of aluminum needed<br />
b. moles of iron formed <br />
c. moles of aluminum oxide formed
Chemistry
1 answer:
Natalija [7]3 years ago
4 0
The answer would be : B
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How do you determine how many molecules are in a chemical equation
V125BC [204]

Answer:

Determine the mass of substance and it's molar mass. Divide the given mass by it's molar mass to get moles and multiply time

6.002*1023 molecules 1mole

5 0
2 years ago
When the equation 
galina1969 [7]

Answer:

The least whole number coefficient for HNO₃ is 6

Explanation:

The chemical equation above is the reaction between calcium orthophosphate and nitric acid.

To balance a chemical equation, we have to consider law of conservation of matter which states that matter can neither be created nor destroyed.

What this law implies is that, whatever we have at the reactant side must be equal to whatever is obtainable at the product side.

The above equation is

Ca₃(PO₄)₂ + HNO₃ → Ca(NO₃)₂ + H₃PO₄

To balance the equation, we'll have to check the number of atoms at each side and possibly balance the equation with the number of moles.

The balanced equation is

Ca₃(PO₄)₂ + 6HNO₃ → 3Ca(NO₃)₂ + 2H₃PO₄

From the balanced equation above, we can see that the number of calcium (Ca), Phosphorus (P), Oxygen(O), Nitrogen(N) and hydrogen (H) are balanced at both sides of the equation.

The least number coefficient for HNO₃ is 6

3 0
3 years ago
Calculate the % composition of the unknown liquid using your most precise result. It is a mixture of ethanol (D[ETOH] = 0.7890 g
Rufina [12.5K]

% composition of ethanol = 34.51%

% composition of water  = 65.49%

<h3>What is density?</h3>

A material's density is defined as its mass per unit volume.

Given data:

The density of ethanol = 0.7890 g/mL

The density of water = 0.9982 g/mL

The density of mixture = 0.926 g/mL

Let the % composition of ethanol = x

Let the % composition of water = 100-x

Now density of the mixture

\frac{Mass}{Volume}

Mass = \frac{percent  \;of  \;ethanol  \;X  \;density  \;of  \;ethanol  \;+  \\ \;percent  \;of  \;water X  \;density  \;of  \;water}{100}

0.926 = \frac{x X  0.7890 g/mL  \;+  (100-x) X  0.9982 g/mL}{100}

x= 34.51 %

Hence,

% composition of ethanol = 34.51%

% composition of water = 65.49%

Learn more about the density here:

brainly.com/question/952755

#SPJ1

8 0
2 years ago
Use a periodic table to help you answer these questions if needed.
yuradex [85]

Answer:

2 Al and 3 S

Explanation:

Al2S3 so 2 Al and 3 S

3 0
1 year ago
How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is C_1_4H_1_8N_2O_5 and it's molar mass is 294.31 grams per mole.

mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

3 0
4 years ago
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