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AfilCa [17]
3 years ago
12

A load of 1 kg is applied to the tip of a cantilever beam with a width b = 2.5 cm, a thickness h = 1 mm, length L = 20 cm, modul

us E = 74 GPa, and density 2.7 g/cm3. What strain is experienced on the bottom surface of the strain gauge 5 cm from the fixed end?
Engineering
2 answers:
Alla [95]3 years ago
6 0

Answer:

20

Explanation:

20 g/cm3 divided by 6 = 20

If my answer qualifies please mark brainliest!

garik1379 [7]3 years ago
4 0

Answer:

20 g/cm3 divide by 6 is 20

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At a point on the free surface of a stressed body, the normal stresses are 20 ksi (T) on a vertical plane and 30 ksi (C) on a ho
victus00 [196]

Answer:

The principal stresses are σp1 = 27 ksi, σp2 = -37 ksi and the shear stress is zero

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The expression for the maximum shear stress is given:

\tau _{M} =\sqrt{(\frac{\sigma _{x}^{2}-\sigma _{y}^{2}  }{2})^{2}+\tau _{xy}^{2}    }

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σx = stress in vertical plane = 20 ksi

σy = stress in horizontal plane = -30 ksi

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Replacing:

32=\sqrt{(\frac{20-(-30)}{2} )^{2} +\tau _{xy}^{2}  }

Solving for τxy:

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The principal stress is:

\sigma _{x}+\sigma _{y} =\sigma _{p1}+\sigma _{p2}

Where

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σp2 = -30 ksi

\sigma _{p1}  +\sigma _{p2}=-10 ksi (equation 1)

\tau _{M} =\frac{\sigma _{p1}-\sigma _{p2}}{2} \\\sigma _{p1}-\sigma _{p2}=2\tau _{M}\\\sigma _{p1}-\sigma _{p2}=32*2=64ksi equation 2

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An insulated piston-cylinder device contains 5 L of saturated liquid water at a constant pressure of 175 kPa. Water is stirred b
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solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment

Download docx
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