Answer:
C.)
Explanation:
The general equilibrium expression looks like this:
In this expression,
-----> K = equilibrium constant
-----> uppercase letters = formulas
-----> lowercase letters = balanced equation coefficients
Solids are not included in the expression, so Ca(HCO₃)₂(s) and CaO(s) should be left out. The products should be in the numerator and the reactants are in the denominator. This makes the expression:
<----- Equilibrium expression
<----- Insert gaseous formulas
<----- Insert coefficients
Answer:
9.55 grams of SiO2
Explanation:
If the mass you mean by grams:
0.159 mole x 60.08 g (Periodic table by adding both elements)
Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:
9.55 grams of SiO2
Answer:
5.97 mol
Explanation:
To find the number of moles when given the mass of a substance, we divide the mass of the sample by its molar mass.
so, we get,
nN203 = 454 g / 76.01 g /mol
= 5.97 mol
Answer:
V CH4(g) = 190.6 L
Explanation:
assuming ideal gas:
∴ STP: T =298 K and P = 1 atm
∴ R = 0.082 atm.L/K.mol
∴ moles (n) = 7.80 mol CH4(g)
∴ Volume CH4(g) = ?
⇒ V = RTn/P
⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)
⇒ V CH4(g) = 190.6 L