How can a charged object cause charges to move within an uncharged object?

1 answer:

3 0

Thank you for posting your question here at brainly. Feel free to ask more questions.
The best and most correct answer among the choices provided by the question is A. If the uncharged object is a conductor, the charged object can attract opposite charges. 

Hope my answer would be a great help for you.

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If the average velocity during the athlete's walk back

goblinko [34]

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

$T=\frac{d}{1.50}$

From the question we are told

If the average velocity during the athlete's walk back to the starting line in Guided Example 2.5 is – 1.50 m/s,

Generally the equation Time spent is mathematically given as

T=\frac{d}{v}

Therefore

$T=\frac{d}{1.50}$

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

$T=\frac{d}{1.50}$

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4 0

3 years ago

At this rate, how long would it take for two continents 3500 kilometers apart to collide?

meriva

Given:

3,500 kilometers

Find:

Years for two continents to collide = ?

Solution:

We know that typical motions of one plate relative to another are 1 centimeter per year.

So first, we convert 3,500 km to cm.

The solution would be like this for this specific problem:

1 km = 100,000 cm

3,500 km x 100,000 = 350,000,000 cm

Since we know that 1 cm = 1 year, then that means 350,000,000 cm is equivalent to 350,000,000 years.

Therefore, it would take 350 million years for two continents that are 3500 kilometers apart to collide.

To add, a phenomenon of the plate tectonics of Earth that occurs at convergent boundaries is called the continental collision.

5 0

3 years ago

A student pushes a 2.85 kg cart causing it to accelerate at a rate of 4.9 m/s squared .What amount of force must the student hav

uysha [10]

In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.

7 0

3 years ago

How much total energy is dissipated in 10. seconds

noname [10]

Answer : Total energy dissipated is 10 J

Explanation :

It is given that,

Time. t = 10 s

Resistance of the resistors, R = 4-ohm

Current, I = 0.5 A

Power used is given by :

$P=\dfrac{E}{t}$