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NNADVOKAT [17]
3 years ago
5

A 13-N east horizontal force acts in the same direction as a 6.4kg block as it slides 2.5m/s on a frictionless, horizontal surfa

ce for 2.1s. What is the speed of the block after force is applied?
Physics
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

6.77 m/s

Explanation:

Acceleration = Force/mass;

The block is accelerated by 13/6.4 m/s^2 for 2.1s from an initial velocity of 2.5m/s.

Applying the equation of motion:

Vf=Vi + at

Where Vf is the final velocity, Vi is the initial velocity, a is the acceleration and t is the time for which the object accelerates.

<h3>Vf= 2.5 + ((13/6.4)*2.1);</h3>
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v₂=velocity of colliding block=4.0m/s

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collecting like terms

4m₂ - 1.8m₂ = 3.96 - 2.64

2.2m₂=1.32

divide both sides by 2.2

m₂= 0.6kg

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