A 13-N east horizontal force acts in the same direction as a 6.4kg block as it slides 2.5m/s on a frictionless, horizontal surfa
1 answer:
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Answer with Explanation:
We are given that
Mass of box=35 kg
Coefficient of static friction between box and truck bed=0.202
Acceleration due to gravity=
a.We have to find the force by which the box accelerates forward.
Force by which box accelerates=
Force by which box accelerates=
b.We have to find the maximum acceleration can the truck have before the box slides.
Force =friction force
Hence, the truck can have maximum acceleration before the box slide=
Answer:
The vertical velocity of the skater upon landing is 10.788 meters per second.
Explanation:
Skateboarder experiments a parabolic movement. As skateboarder jumps horizontally off the top of the staircase, it means that vertical component of initial velocity is zero and accelerates by gravity, the final vertical speed is calculated by the following expression:
Where:
- Initial vertical speed, measured in meters per second.
- Final vertical speed, measured in meters per second.
- Gravitational acceleration, measured in meters per square second.
- Time, measured in seconds.
Given that ,
and
, the final velocity of the skater upon landing is:
The vertical velocity of the skater upon landing is 10.788 meters per second.