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algol [13]
3 years ago
10

How strong would the gravitational attraction be (in units of Earth-pulls) between a Saturn-like planet and the Sun, if the plan

et is 98 Earth-masses and is located at 9.23 AU from the Sun?
Physics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

Explanation:

be (in units of Earth-pulls) between a Saturn-like planet and the Sun, if ... ... Sun, If The Planet Is 98 Earth-masses And Is Located At 9.23 AU From The Sun?

Hope this helps! Have a splendid day!

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Which of the following is an example or an orginasm mantaining homeostasis
Kryger [21]

a cat grooming itself

8 0
3 years ago
A uniform rod of mass M and length L can pivot freely at one end. Initially, the rod is oriented vertically above the pivot, in
Leya [2.2K]

Answer:

The speed of its center of mass =\sqrt{\frac{3}{2}gL}

Explanation:

Consider the potential energy at the level of center of mass of rod below the pivot=0

Mass of uniform rod=M

Length of rod=L

The rotational inertia about the end of a uniform rod=\frac{1}{3}ML^2

Kinetic energy at the level of center of mass of rod below the pivot=\frac{1}{2}I\omega^2

Kinetic energy at the level of center of mass of rod above the pivot=0

Potential energy at the level of center of mass of rod above the pivot=mgh

We have to find the center of mass ( in terms of g and L).

According to conservation of law of energy

Initial P.E+Initial K.E=Final P.E+Final K.E

mgh+0=0+\frac{1}{2} I\omega^2

Where K.E=\frac{1}{2} I\omega^2

I=Moment of inertia

\omega=Angular velocity

Substitute the values then we get

MgL=\frac{1}{2}\times \frac{1}{3}ML^2\omega^2

\omega^2=\frac{6g}{L}

Now, we know that \omega=\frac{v}{r}, r=\frac{L}{2}

Substitute the values then we get

\frac{v^2}{(\frac{L}{2})^2}=\frac{6g}{L}

\frac{v^24}{L^2}=\frac{6g}{L}

v^2=\frac{6g\times L^2}{4L}

v^2=\frac{3gL}{2}

v=\sqrt{\frac{3}{2}gL}

Hence, the speed of its center of mass =\sqrt{\frac{3}{2}gL}

4 0
4 years ago
Newton’s laws of motion are an inherent part of our everyday life. Starting from the beginning of the day till the end, Newton’s
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1st

Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: Law 1. A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.

2nd

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

3rd

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions.

hope this helps u :)

6 0
2 years ago
What does it mean if an AA battery has 1.5V written on the side of it?
Pie
It means that the potential difference between the metal can and the little button on top of the battery is about 1.5 volts.

That's strictly the result of the chemicals in the battery, and has nothing to do with its size.  If a battery as big as a house has the same chemistry inside that the AA has, the big one will also have 1.5 volts between its terminals.  (But it'll run your flashlight much longer than the AA will, before it runs down.)
3 0
4 years ago
Read 2 more answers
Three resistors of equal resistance are connected in series as shown. Compared to the voltage provided by the battery, voltage a
dsp73

Answer:

the voltage across each resistor is one third of the battery voltage

Explanation:

In a series circuit, the current is constant throughout the circuit, so the battery voltage is equal to the sum of the voltage drop in each part of the series circuit.

        V = i (R₁ + R₂ + R₃)

       

in the exercise indicate that all resistance has the same value

         R₀ = R₁ = R₂ = R₃

        V = i 3 R₀

        V = 3 V₀

         V₀ = i R₀

          V₀= V / 3

the voltage across each resistor is one third of the battery voltage

6 0
3 years ago
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