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malfutka [58]
3 years ago
6

A bullet of 10g strikes a sand bag at a speed of 100 m/s and gets embedded after travelling

Physics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

Solving for time :

(There are 4 formulas from linear motion. These formulas are very helpful as it allows us to prevent complicated calculations. Choose among the four that has : 1. The most constants known

2. The unknown constant that we want to solve)

s = (1/2)(u+v)t <--- one of the formulas

from linear motion

s (distance) = 0.05m

u (initial velocity) = 100m/s

v (final velocity) = 0 m/s (it stops)

t (time taken for change in velocity) = to be found

0.05 = (1/2)(100+0)t

t = 0.001 seconds

Solving for the resistant force :

Since the bullet hits the bag with an impulsive force and stops, the force that stops the bullet is the resistant force.

When the bullet stops :

F net = 0

F r = F imp

F r = (mu -mv)/t

F r = (0.01x100-0.01x0)/0.001

F r = 1/0.001

F r = 1000N

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Answer:

You have to calculate

Explanation:

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Answer:

The value is   t =  14.129 \  minutes    

Explanation:

From the question we are told that

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Generally the time taken is mathematically represented as

     t =  \frac{d}{c}

=> t =  \frac{2.543*10^{11}}{3.0*10^{8} }

=>    t =  847.7 \  s

Now converting to minutes

       t =  \frac{847.7}{60}

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Explanation:

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