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KatRina [158]
4 years ago
12

The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 x 106 Btu/h. The comb

ustion efficiency of the boiler is measured to be 0.65. After tuning up the boiler, the combustion efficiency rises to 0.75. The boiler operates 4000 hours a year intermittently. Take the unit cost of energy to be $4.35/106 Btu. Assuming the same heat output for before and after the tunning:________.
Engineering
1 answer:
Veronika [31]4 years ago
7 0

Answer:

Explanation:uhhhhhh all?

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University administrators have developed a Markov model to simulate graduation rates at their school. Students might drop out, r
abruzzese [7]

Solution :

The percentage of the students who have a chance of repeating their current year = 3%

The drop out students for the first year and the sophomores = 6%

Drop out rate of first year and the seniors = 4%

Now for the state space :

S = { first year(1), sophomores(2), juniors(3), seniors(4), graduates(G), Dropouts(D) }

Therefore

the first year students are indicated as '1'

Sophomores are indicated as '2'

Juniors are indicated as '3'

Seniors are indicated as '4

Graduates are indicated as 'G'

Dropouts are indicated as 'D'

The transition diagram is attached below.

The probability of the students who have the chance of repeating their current year = 3/100 = 0.03

Probability of first year dropouts and sophomores = 6/100 = 0.06

Probability of dropout rate of juniors and seniors = 4/100 = 0.04

Therefore, the probability matrix can be made as :

              1        2        3        4       G        D

    \begin{matrix}1\\ 2\\ 3\\ 4\\ G\\ D\end{matrix}      \begin{bmatrix}0.03 & 0.91 & 0 & 0 & 0 & 0.06\\  0& 0.03 & 0.91 & 0 & 0 & 0.06\\  0& 0 & 0.03 & 0.93 & 0 & 0.04\\  0& 0 & 0 & 0.03 & 0.93 & 0.04\\  0& 0 & 0 & 0 & 1 & 0\\  0& 0 & 0 & 0 & 0 & 1\end{bmatrix}  

Here, G represents 'graduates' and D represents 'Dropouts.'

5 0
3 years ago
If increased productivity in the workplace is an example of the macroeconomic impact of the green economy and increased income f
Ivan

option 2 is your answer... thanks .. hope it helps

7 0
3 years ago
Given a force of 72 lbs at a distance of 15 ft, calculate the moment produced.​
Elis [28]

Answer:

1425.78 N.m

Explanation:

Moments of force is calculated as ;

Moments= Force * distance

M= F*d

The S.I unit for moment of force is Newton-meter (N.m)

Given in the question;

Force = 72 lbs

1 pound = 4.45 N

72 lbs = 4.45 * 72=320.4 N

Distance= 15 ft

1ft= 0.3048 m

15 ft = 15*0.3048 = 4.57 m

d= 4.57 m

M= F*d

M=320.4*4.57 =1425.78 N.m

5 0
4 years ago
Which of the following is lost when the computer is turned off? ILL MARK BRAINLEST
Pavel [41]

Answer:

cloud storage is the answer

6 0
3 years ago
Read 2 more answers
A car hits a tree at an estimated speed of 10 mi/hr on a 2% downgrade. If skid marks of 100 ft. are observed on dry pavement (F=
Dafna11 [192]

Answer:

v_{o} = 22.703\,\frac{m}{s} \left(50.795\,\frac{m}{s}\right)

Explanation:

The deceleration of the car on the dry pavement is found by the Newton's Law:

\Sigma F = -\mu_{k,1}\cdot m\cdot g \cdot \cos \theta + m\cdot g \cdot \sin \theta = m\cdot a_{1}

Where:

a_{1} = (-\mu_{k,1}\cdot \cos \theta + \sin \theta)\cdot g

a_{1} = (-0.33\cdot \cos 1.146^{\textdegree}+\sin 1.146^{\textdegree})\cdot \left(9.807\,\frac{m}{s^{2}} \right)

a_{1} = -3.040\,\frac{m}{s^{2}}

Likewise, the deceleration of the car on the unpaved shoulder is:

a_{2} = (-\mu_{k,2}\cdot \cos \theta + \sin \theta)\cdot g

a_{2} = (-0.28\cdot \cos 1.146^{\textdegree}+\sin 1.146^{\textdegree})\cdot \left(9.807\,\frac{m}{s^{2}} \right)

a_{2} = -2.549\,\frac{m}{s^{2}}

The speed just before the car entered the unpaved shoulder is:

v_{o} = \sqrt{\left(4.469\,\frac{m}{s} \right)^{2}-2\cdot \left(-2.549\,\frac{m}{s^{2}} \right)\cdot (60.88\,m)}

v_{o} = 18.175\,\frac{m}{s}

And, the speed just before the pavement skid was begun is:

v_{o} = \sqrt{\left(18.175\,\frac{m}{s} \right)^{2}-2\cdot \left(-3.040\,\frac{m}{s^{2}} \right)\cdot (30.44\,m)}

v_{o} = 22.703\,\frac{m}{s} \left(50.795\,\frac{m}{s}\right)

8 0
3 years ago
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