Answer:
i) 0.610 m or 610 mm
ii) 0.4 m or 400 mm
Explanation:
The pressure difference between the pipes is
a) Air
Pa + πha +Ha = Pb + πhb +Hb
Pa - Pb = π(hb-ha) + Hb-Ha
Relative density of air = 1.2754 kg /m3
Pa - Pb = 1.2754 * 0.4 + (0.3-0.2) = 0.610 m or 610 mm
b) paraffin of relative density of 0.75
Pa - Pb = π(hb-ha) + Hb-Ha
Pa - Pb = 0.75 * 0.4 + (0.3-0.2) = 0.4 m or 400 mm
Answer:
Q= 4.6 × 10⁻³ m³/s
actual velocity will be equal to 8.39 m/s
Explanation:
density of fluid = 900 kg/m³
d₁ = 0.025 m
d₂ = 0.05 m
Δ P = -40 k N/m²
C v = 0.89
using energy equation
under ideal condition v₁² = 0
v₂² = 88.88
v₂ = 9.43 m/s
hence discharge at downstream will be
Q = Av
Q = 
Q = 
Q= 4.6 × 10⁻³ m³/s
we know that
hence , actual velocity will be equal to 8.39 m/s
Answer:
Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37
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sorry for errors
No ground to connect to show me attach to any terminal or lead size reverse designated polarity
Answer B.False
The current draw that should be used for the test by the technician when charging the battery is C. 600 amps for 30seconds.
<h3>Who is a technician?</h3>
It should be noted that a technician simply means an individual that is in charge of a technical equipment.
In this case, since the technician is load testing a fully charged battery rated at 600 cold-cranking amps, the current draw that should be used is 600 amps for 30seconds.
Learn more about technicians on:
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