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3 years ago

Consider the following equilibrium:H2CO3(aq) + H2O(l) H3O+(aq) + HCO3-1(aq).What is the correct equilibrium expression?

1 answer:

8 0

1. The equilibrium expression shows the ratio between products and reactants. This expression is equal to the concentration of the products raised to its coefficient divided by the concentration of the reactants raised to its coefficient. The correct equilibrium expression for the given reaction is:

H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]

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How many moles of aluminum oxide (Al2O3) can be produced from 12.8 moles of oxygen gas (02)

zhannawk [14.2K]

Answer:

Theoretical Yield

Percent yield

Example stoichiometry problem

How much oxygen can be prepared from 12.25 g KClO3 . (Use molar mass KClO3 = 122.5 g.)

Most stoichiometry problems can be solved using the following steps.

Step 1.

Write and balance the equation for the decomposition of KClO3 with heat (∆). 2KClO3 + ∆ → 2KCl + 3O2

Step 2.

Convert what you have (in this case g KClO3) to moles.

# moles = grams/molar mass = 12.25 g /122.5 = 0.100 mole KClO3.

Step 3.

Using the coefficients in the balanced equation, convert moles of what you have (moles KClO3) to moles of what you want (in this case moles oxygen).

0.100 mol KClO3 x (3 moles O2/2 moles KClO3) = 0.100 x (3/2) = 0.150 mole O2.

Step 4.

Convert moles from step 3 to grams.

moles x molar mass = grams

0.150 mole O2 x (32.0 g O2/mole O2) = 4.80 g O2 produced from 12.25 g KClO3. This is the theoretical yield. If the ACTUAL yield is 4.20 grams, calculate percent yield. Percent yield = (actual yield/theoretical yield) x 100 = (4.20/4.80) x 100 = 87.5% yield

NOTE: In step 1, moles can be obtained other ways; in step 4 moles can be converted to other units.

a. For solutions, M x L = moles (or mL x M = millimoles).

b. For gases, L/22.4 = moles

4 0

3 years ago

What is the total mass of Hydrogen in each of the molecules?

frutty [35]

Explanation:

a) In 1 mole of methane there are 4 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 4 × 1 g = 4 g

b) In 1 mole of chloroform there are 1 mole of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 1× 1 g = 1 g

c) In 1 mole of $C_{12}H_{10}O_{16}$ there are 10 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of $C_{12}H_{10}O_{16}$ = 10 × 1 g = 10 g

d)In 1 mole of $CH_3CH_2CH_2CH_2CH_3$ there are 12 moles of hydrogen atom.

$CH_3CH_2CH_2CH_2CH_3=C_5H_{12}$

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of $CH_3CH_2CH_2CH_2CH_3$ = 12 × 1 g = 12 g

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4 years ago

Determining nitrogen balance in the clinical setting can be very valuable. To determine a client’s state of nitrogen balance, a

nikdorinn [45]

Answer:

We also need the nitrogen intake

Explanation:

The nitrogen balance is the difference between the nitrogen intake and nitrogen excreted. If this calculation is positive, the body grow; if it is negative, the body is decreased.

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3 years ago

How do Earth’s plates able to move?

Ann [662]

Answer:

Plates at our planet's surface move because of the intense heat in the Earth's core

Explanation:

Hopefully this helps, I believe in you! ^^

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3 years ago

Read 2 more answers

What is/are the product(s) of a neutralization reaction of a carboxylic acid? View Available Hint(s) What is/are the product(s)

lutik1710 [3]

Answer:

A carboxylate salt and water

Explanation:

A carboxylic acid is an organic compound that has general formula RCOOH, where R is a carbon chain. Because it's an acid, the neutralization will happen when it reacts with a base, such as NaOH.

When this reaction occurs, the base will dissociate in Na⁺ and OH⁻, and the acid will ionize in RCOO⁻ and H⁺, so the products will be RCOO⁻Na⁺ (a carboxylate salt) and H₂O (water).

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3 years ago