Missing question (found on internet):
"what is the force of the car?"
Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:

For the car in the problem,


So the force that accelerates the car is
Answer:
f = 614.28 Hz
Explanation:
Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :


f = 614.28 Hz
So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.
Mass of yellow train, my = 100 kg
Initial Velocity of yellow train, = 8 m/s
mass of orange train = 200 kg
Initial Velocity of orange train = -1 m/s (since it moves opposite direction to the yellow train, we will put negative to show the opposite direction)
To calculate the initial momentum of both trains, we will use the principle of conservation of momentum which
The sum of initial momentum = the sum of final momentum
Since the question only wants the sum of initial momentum,
(100)(8) + (200)(-1) = 600 m/s
Answer:
270 m
Explanation:
We can find the distance travelled by the car by using the following suvat equation:

where
s is the distance travelled
u is the initial velocity
v is the final velocity
t is the time
For the car in this problem,
u = 0
v = 45 m/s
t = 12 s
Substituting into the equation, we find:

The speed of the car at the bottom of the hill is obtained as, 
According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.

where;
- <em>v </em><em>is the speed of the car at the bottom of the hill</em>
- <em>h </em><em>is the height of the hill</em>
- <em>g </em><em>is acceleration due to gravity</em>
Thus, the speed of the car at the bottom of the hill is obtained as, 
Learn more about conservation mechanical energy here: brainly.com/question/332163