Answer:
As P is continually increased, the block will now slip, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, with f remaining constant thereafter as P is increased.
Answer:
Explanation:
Before: PT= 0.10, PB= 0.03 (given) ET = 2.5 ER = 2.0 (Table 6.5)
fHV= 0.847 (Eq. 6.5) PHF = 0.95, fp= 0.90, N=2, V = 2200 (given)
vp= V/[PHF⋅fHVTB⋅fp⋅N] = 1518.9 (Eq. 6.3)
BFFS = 50+5, BFFS =55 (given) fLW= 6.6
TLC=6+3=9 fLC= 0.65
fM= 0.0
fA= 1.0
FFS = BFFS −fLW−fLC–fM–fA= 46.75 (Eq. 6.7)
Use FFS=45 D= vp/S = 33.75pc/mi/ln Eq (6.6)
After: fA= 3.0
FFS = BFFS −fLW−fLC–fM–fA= 44.75 (Eq. 6.7)
Use FFS=45 Vnew= 2600 Vp= Va/[PHF⋅fHB⋅fp⋅N] = 1795 (Eq. 6.3) D= vp/S = 39.89pc/mi/ln
I’m just here for points because I have test and I need them lol
Answer:
Explanation:
Heat engine
Heat engine is a device which produce work while consuming some amount of energy .This engine works in cycle.In other words we can say that Heat engine is a device which covert thermal or chemical energy in to mechanical energy and after that this mechanical energy can be use for producing mechanical work.
Heat engine takes heat from high temperature and rejects heat to lower temperature and producing work.
We know that efficiency given as
From diagram we can say that
So efficiency
Answer & Explanation:
//written in java
public class Main {
public static void main(String[] args) {
//declare a char variable for a, b, c
char a;
char b;
char c;
//assign a b and c
//a b and c can be replaced for with
// '#', '$', '%', then with '1', '2', '3'
// for further testing
a = 'x';
b = 'y';
c = 'z';
//output for all possible combination for a, b, c.
System.out.println("" + a + b + c + " " + a + c + b + " " + b + a + c +
" " + b + c + a + " " + c + a + b + " " + c + b + a);
}
}
