The pKa of the dimethylammonium ion, (CH₃)₂NH₂⁺ is 10.7.
<h3>
What do we know about dimethylammonium ion?</h3>
The conjugate acid of dimethylamine, dimethylaminium is an organic cation and a significant species at pH 7.3. It is a secondary aliphatic ammonium ion and an organic cation. It is a dimethylamine conjugate acid.
<h3>What do we understand by pKa?</h3>
In layman's terms, pKa is a measurement of an acid's strength. A strong acid will have a pKa value that is lower than 0. To be more specific, pKa is the Ka value's negative log base ten value (acid dissociation constant). How tightly a proton is retained by a Bronsted acid is how the strength of an acid is measured. The strength of the acid and its capacity to donate protons increase with decreasing pKa values.
To learn more about pKa:
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Answer:
Partial pressure for each of the three gases, in the mixture is 15 atm
Explanation:
Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.
Our total pressure = 45 atm
The 3 gases have the same pressure, so we can propose this equation:
3x = 45 atm
where x is the partial pressure for each of the three gases.
x = 45/3 → 15 atm
Answer:
C. 3.0
Explanation:
Bond order is number of the bonding pairs of the electrons between two atoms.
For
,
The total number of the valence electrons = 2(4) + 1(5) + 3(1) = 16
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
The Lewis structure is:
H
:
H : C : C : : : N :
:
H
Bond pairs between C and N is 3
<u>So bond pair is 3.</u>
Answer:

Explanation:


282000 j/mol *1 mol/6*10^(23) = 4.7*10^(-19) J for one electron

Answer:
The answer is
<h2>1479.60 mL</h2>
Explanation:
In order to calculate the volume needed we use the formula

where
C1 is the concentration of the stock solution
V1 is the volume of the stock solution
C2 is the concentration of the diluted solution
V2 is the volume of thevdiluted solution
From the question
C1 = 1.45 M
V1 = 25 mL
C2 = 0.0245 M
So we have

We have the final answer as
<h3>1479.60 mL</h3>
Hope this helps you