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Virty [35]
3 years ago
7

Jared is practicing for a golf tournament. His normal driver distance is 250 yards. He hits three balls with his driver, and the

y travel a distance of 190 yards, 195 yards, and 187 yards. Which of the following is true?
His drives are precise but not accurate

His drives are accurate but not precise

His drives are neither precise not accurate

His drives are both accurate and precise
Chemistry
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

His drives are neither precise not accurate

Explanation:

It is true that his drives are neither precise nor accurate.

Accuracy is the exactness of measurement. It is the closeness of measured values to the true values.

In this problem, the true value is 250 yards, the measured values are 190 yards, 195 yards and 187 yards.

We can conclude that these numbers are very far from the true values. By virtue of that, they are inaccurate.

Precision is the ability to reproduce a set of experimental values. It is the closeness of the measured values to one another.

Jared failed to replicate his measured values over the three trials and so, his readings are not precise.

Therefore, his measurements are both imprecise and inaccurate.

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(b) What is the pKa of the dimethylammonium ion, (CH₃)₂NH₂⁺ ?
g100num [7]

The pKa of the dimethylammonium ion, (CH₃)₂NH₂⁺ is 10.7.

<h3>What do we know about  dimethylammonium ion?</h3>

The conjugate acid of dimethylamine, dimethylaminium is an organic cation and a significant species at pH 7.3. It is a secondary aliphatic ammonium ion and an organic cation. It is a dimethylamine conjugate acid.

<h3>What do we understand by pKa?</h3>

In layman's terms, pKa is a measurement of an acid's strength. A strong acid will have a pKa value that is lower than 0. To be more specific, pKa is the Ka value's negative log base ten value (acid dissociation constant). How tightly a proton is retained by a Bronsted acid is how the strength of an acid is measured. The strength of the acid and its capacity to donate protons increase with decreasing pKa values.

To learn more about pKa:

brainly.com/question/13178964

#SPJ4

7 0
1 year ago
12. If the total pressure exerted by 3 gases is 45 atm and each individual gas has the
Bumek [7]

Answer:

Partial pressure for each of the three gases, in the mixture is 15 atm

Explanation:

Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.

Our total pressure = 45 atm

The 3 gases have the same pressure, so we can propose this equation:

3x = 45 atm

where x is the partial pressure for each of the three gases.

x = 45/3 → 15 atm

3 0
4 years ago
What is the bond order for the carbon-nitrogen bond in acetonitrile, CH3CN? 2.2.0 03.0.5 C. 3.0 d. 1.5 0.1.0
marin [14]

Answer:

C. 3.0

Explanation:

Bond order is number of the bonding pairs of the electrons between two atoms.

For CH_3CN,

The total number of the valence electrons  = 2(4) + 1(5) + 3(1) = 16

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,  

The Lewis structure is:

          H

           :                  

H   :    C   :   C   :  :  :   N :

           :

          H

Bond pairs between C and N is 3

<u>So bond pair is 3.</u>

7 0
3 years ago
Read 2 more answers
In hypothetical element, two energy levels are separated by an energy of 282 kj/mol. what wavelength of light (in nm) is involve
scZoUnD [109]

Answer:

4.23*10^2 nm = 423 nm

Explanation:

E={\frac  {hc}{\lambda }}

h=6.62607015*10^{-34}J*s\\c=299 792 458 m / s\\h*c=1.98644568*10^{-25}J*m

282000 j/mol *1 mol/6*10^(23) = 4.7*10^(-19) J for one electron

\lambda={\frac  {hc}{E }}=\frac{1.98644568*10^{-25}J*m}{4.7*10^{-19}J} =\\\\=4.22648017*10^{-7} m = 4.22648017*10^{-7} m*\frac{10^9 nm}{1 m} =\\\\4.23*10^2 nm = 423 nm

6 0
3 years ago
To what volume (in mL) would you need to dilute 25.0mL of a 1.45 m solution of Kcl to make a 0.0245m solution of KCl
dezoksy [38]

Answer:

The answer is

<h2>1479.60 mL</h2>

Explanation:

In order to calculate the volume needed we use the formula

V_2 =  \frac{C_1V_1}{C_2}

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the diluted solution

V2 is the volume of thevdiluted solution

From the question

C1 = 1.45 M

V1 = 25 mL

C2 = 0.0245 M

So we have

V_2 =  \frac{1.45 \times 25}{0.0245}   =  \frac{36.25}{0.0245}  \\  = 1479.59...

We have the final answer as

<h3>1479.60 mL</h3>

Hope this helps you

4 0
3 years ago
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