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Virty [35]
3 years ago
7

Jared is practicing for a golf tournament. His normal driver distance is 250 yards. He hits three balls with his driver, and the

y travel a distance of 190 yards, 195 yards, and 187 yards. Which of the following is true?
His drives are precise but not accurate

His drives are accurate but not precise

His drives are neither precise not accurate

His drives are both accurate and precise
Chemistry
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

His drives are neither precise not accurate

Explanation:

It is true that his drives are neither precise nor accurate.

Accuracy is the exactness of measurement. It is the closeness of measured values to the true values.

In this problem, the true value is 250 yards, the measured values are 190 yards, 195 yards and 187 yards.

We can conclude that these numbers are very far from the true values. By virtue of that, they are inaccurate.

Precision is the ability to reproduce a set of experimental values. It is the closeness of the measured values to one another.

Jared failed to replicate his measured values over the three trials and so, his readings are not precise.

Therefore, his measurements are both imprecise and inaccurate.

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Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)
steposvetlana [31]
Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
      = (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
      = 176.15 kJ - 84.78 kJ = 91.38 kJ 
 





 
6 0
3 years ago
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Someone tell me if I'm right​
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Answer:

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