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3 years ago

When an x-ray photon passes through matter it undergoes a process called:_________.

Physics

1 answer:

bekas [8.4K]3 years ago

5 0

Answer:

when an x-ray passes trough matter, it undergoes a process called attenuation

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While it’s impossible to design a perpetual motion machine, that is, a machine that keeps moving forever, come up with ways to k

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3 years ago

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Which type of energy is associated with electric currents?

zalisa [80]

B. Electrical energy

Among the choices given, the type of energy associated with electric currents is electrical energy. By its definition, electric current is the flow of charged particles through a conductor or a conduction medium, for example, a wire. Basically, it involves electricity. It is similar to water current but instead of water molecules, charged particles move down a conductor. These charged particles are mostly electrons which move freely and at random. When all the free electrons move in the same direction, a current is created.

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3 years ago

If a balloon lands 33m away,what is the height of the building?

igor_vitrenko [27]

Is the initial velocity or time given?

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3 years ago

The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca

Verizon [17]

Answer:

The value is $E_i = 1.5596 *10^{-18} \ J$

Explanation:

From the question we are told that

The wavelength is $\lambda = 48.2 nm = 48.2 *10^{- 9 }\ m$

The velocity is $v = 2.371*10^6 \ m/s$

The mass of electron is $m_e = 9.109*10^{-31} \ kg$

Generally the energy of the incident light is mathematically represented as

$E = \frac{h * c}{\lambda}$

Here c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

h is the Planck constant with value $h = 6.62607015 * 10^{-34 } J\cdot s$

$E = \frac{6.62607015 * 10^{-34 }* 3.0 *10^{8}}{48.2 *10^{- 9 }}$

=> $E = 4.12 *10^{-18} \ J$

Generally the kinetic energy is mathematically represented as

$E_k = \frac{1}{2} * m_e * v^2$

=> $E_k = \frac{1}{2} * 9.109*10^{-31} * (2.371*10^6 )^2$

=> $E_k = 2.56 *0^{-18} \ J$

Generally the ionization energy is mathematically represented as

$E_i = 4.12 *10^{-18} - 2.56 *0^{-18}$

=> $E_i = 1.5596 *10^{-18} \ J$

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