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____ [38]
3 years ago
9

A large number of hydrogen atoms are excited from the ground state to the state with n = 4. At how many different wavelengths ma

y photons be emitted by this group of atoms?
Physics
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

6

Explanation:

Following are the possible transition

1 ) 4 to 3

2) 4 to 2

3) 4 to 1

4 ) 3 to 2

5 ) 3 to 1

6 ) 2 to 1 .

There are altogether 6 wavelengths of photons possible .

This result can be achieved with the help of permutation and combination.

No of ways in which 2 things can be selected out of 4 things , combination being all different.

₂C⁴ = (4 X 3) / 2 = 6.

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The container was lifted a height of 14 m
Alika [10]
Work done = Force X Distance

3 430 000J = Force X 14m

Force = 3 430 000J / 14m
= 245 000 N

Hope this helps!
8 0
2 years ago
I just need an answer ASAP
nikdorinn [45]

Answer: c

Explanation: hope this helps :)

8 0
3 years ago
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When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Stella [2.4K]

Answer:

it is separated by 80 cm distance

Explanation:

As per Coulombs law we know that force between two point charges is given by

F = \frac{kq_1q_2}{r^2}

here we know that

q_1 = +8.4\mu C

q_2 = +5.6 \mu C

force between two charges is given as

F = 0.66 N

now we have

F = \frac{kq_1q_2}{r^2}

0.66 = \frac{(9\times 10^9)(8.4 \mu C)(5.6 \mu C)}{r^2}

r = 0.8 m

so it is separated by 80 cm distance

3 0
3 years ago
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Light of wavelength 578.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 62.5 cm from the slit.
yaroslaw [1]

Answer:

80.6\mu m

Explanation:

When light passes through a narrow slit, it produces a diffraction pattern on a distant screen, consisting of several bright fringes (constructive interference) alternated with dark fringes (destructive interference).

The formula to calculate the position of the m-th maximum in the diffraction pattern produced in the screen is:

y=\frac{m\lambda D}{d}

where

y is the distance of the m-th maximum from the central maximum (m = 0)

\lambda is the wavelength of light used

D is the distance of the screen from the slit

d is the width of the slit

In this problem, we have:

\lambda=578.0 nm = 578\cdot 10^{-9} m is the wavelength

D = 62.5 cm = 0.625 m is the distance of the screen

We know that the distance between the third order maximum (m=3) and the central maximum is 1.35 cm (0.0135 m), which means that

y_3 = 0.0135 m

For

m = 3

Therefore, rearranging the equation for d, we find the width of the slit:

d=\frac{m\lambda D}{y_3}=\frac{(3)(578\cdot 10^{-9})(0.625)}{0.0135}=80.3\cdot 10^{-6} m=80.6\mu m

8 0
4 years ago
When compared to strong nuclear force gravitational force is
pickupchik [31]
Answer is A
Gravitational force is substantially weaker than the strong nuclear force.
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4 years ago
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