Answer:
The change in kinetic energy per unit mass of water flowing through the valve is - ΔKE = 0.025 KJ/Kg
Explanation:
Knowing
-Fluid is air
-inlet 1: P1 = 300 kPa
-exit 2: P2 = 275 kPa
density - rho= 1000 kg/m3
Using the formula
Δh = cΔT + Δp/rho
as change in temperature is neglected then change in enthalpy becomes
Δh = Δp/rho
energy equation could be defined by
Q - W = m(out) [h(out) (out)/2 + g Z(out)] - m(in) [h(in) (in)/2 + g Z(in)]
Q - W = m2 [h2 2/2 + g Z2] - m1 [h1 1/2 + g Z1]
as for neglecting potential energy effects
Q - W = m2(h2) - m1(h1)
as the system is adiabatic and has no work done
0 = m2 [h2 2/2] - m1 [h1 1/2]
from mass balance m1 = m2
0 = [h2 2/2] - [h1 1/2]
Change in kinetic energy could be defined by
ΔKE = 2/2 - 1/2
Change in specific enthalpy could be defined by
Δh = h2 - h1
Then the change in kinetic energy per unit mass of water flowing through the valve could be calculated as following
ΔKE = -Δh = ΔP/rho
-(275 - 300)/1000 = 0.025 KJ/Kg
- ΔKE = 0.025 KJ/Kg
Street joints need to be clamped for atleast 24 hours
Answer:
the entrained fluid flowrate is 150 liters/s
Explanation:
Given the data in the question;
we determine the flow rate of water though the jet by using the following expression;
Q₂ = A₂ × V₂
where Q₂ is the flow rate of water though the jet, A₂ is the cross sectional area of the jet( 0.01 m² ) and V₂ is the jet velocity( 30 m/s )
so we substitute
Q₂ = 0.01 m² × 30 m/s
Q₂ = 0.3 m³/s
Next we determine the flow rate of water through the pump by using the following expression
Q₃ = A₃ × V₃
where Q₃ is the flow rate of water though the pump, A₃ is the cross sectional area of the pump( 0.075 m² ) and V₃ is the average velocity of mixing( 6 m/s )
so we substitute
Q₃ = 0.075 m² × 6 m/s
Q₃ = 0.45 m³/s
so to calculate the flow pumping rate of water into the water jet pump, we use the expression;
Q₁ + Q₂ = Q₃
we substitute
Q₁ + 0.3 m³/s = 0.45 m³/s
Q₁ = 0.45 m³/s - 0.3 m³/s
Q₁ = 0.15 m³/s
we know that 1 m³/s = 1000 Liter/second
so
Q₁ = 0.15 × 1000 Liter/seconds
Q₁ = 150 liters/s
Therefore, the entrained fluid flowrate is 150 liters/s
Answer:
2000x + 1400 N-m
Explanation:
The torque at a given point is determined as the perpendicular force multiply by the distance of the force from the given point. The conventional method is to take clockwise direction as positive and anticlockwise direction as negative. Therefore:
Torque at the segment AB = 2000*x + 400 = (2000x + 400) N-m
Answer: if most people are driving the way that you are
Explanation:the law of the many