Explanation:
Gravitational force is given by
G=6.674×10⁻¹¹ m³⋅kg⁻¹⋅s⁻²
M = Mass of object 1
m = mass of object 2
r = Distance between objects.
Here only variable is r value.
In case 1
In case 2
Option C is the correct answer.
Answer:
0.37 cm
Explanation:
The image is formed on the retina which is at a constant distance of 2.70 cm to the lens. Therefore, image distance = 2.70 cm.
The object is at a distant of 265 cm to the lens of the eye.
From lens formula,
=
+
where: f is the focal length, u is the object distance and v is the image distance.
Thus, u = 265.00 cm and v = 2.70 cm.
=
+
=
=
⇒ f =
= 0.37
The focal length of the eye is 0.37 cm.
Answer:
U = 25 J
Explanation:
The energy in a set of charges is given by
U =
in this case we have three charges of equal magnitude
q = q₁ = q₂ = q₃
with the configuration of an equilateral triangle all distances are worth
d = a
U = k ( )
we substitute
15 = k q² (3 / a)
k q² /a = 5
For the second configuration a load is moved to the measured point of the other two
d₁₃ = a
The distance to charge 2 that is at the midpoint of the other two is
d₁₂ = d₂₃ = a / 2
U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})
U = k q² ( )
U = (kq² /a) 5
substituting
U = 5 5
U = 25 J