Answer:
The solid sphere will reach the bottom first.
Explanation:
In order to develop this problem and give it a correct solution, it is necessary to collect the concepts related to energy conservation. To apply this concept, we first highlight the importance of conserving energy so we will match the final and initial energies. Once this value has been obtained, we will concentrate on finding the speed, and solving what is related to the Inertia.
In this way we know that,
We know as well that the lineal and angular energy are given by,
And the tangential kinetic energy as
Where
Replacing
Re-arrange for v,
We have here three different objects: solid cylinder, hollow pipe and solid sphere. We need the moment inertia of this objects and replace in the previous equation found, then,
For hollow pipe:
For solid cylinder:
For solid sphere,
Then comparing the speed of the three objects we have:
Answer:
The mass of the massive object at the center of the Milky Way galaxy is
Explanation:
Given that,
Diameter = 10 light year
Orbital speed = 180 km/s
Suppose determine the mass of the massive object at the center of the Milky Way galaxy.
Take the distance of one light year to be 9.461×10¹⁵ m. I was able to get this it is 4.26×10³⁷ kg.
We need to calculate the radius of the orbit
Using formula of radius
We need to calculate the mass of the massive object at the center of the Milky Way galaxy
Using formula of mass
Put the value into the formula
Hence, The mass of the massive object at the center of the Milky Way galaxy is
Large telescopes aren't built on mountain tops for the purpose of watching
weather systems. The ones that are built at high altitudes are intended to be
used to observe celestial objects ... planets, stars, galaxies, comets, nebulae,
quasars, novae, and the space around black holes.
The way a telescope does that is: It collects visible light and radiation with
other electromagnetic wavelengths, and people then analyze the radiation
that the telescope has collected.
When we use the telescope to do that, we want anything it collects to be
as close as possible to the radiation that actually left the star. The problem
is that anything the telescope collects must come down through AIR. The trip
through air changes the radiation before you have a chance to collect it, so
you can never see exactly what left the star.
The solution:
==> Build your telescope in a place where the light goes through less air
before it reaches the telescope.
==> Or ... if you can work it out somehow ... through NO air.
That means:
==> Build your telescope at high altitude, on a mountaintop, where
most of the Earth's air is BELOW you.
==> Or put your telescope in a spacecraft. Put the spacecraft in orbit
around the Earth, where there is almost NO air, and let the telescope
send its pictures and other data to you by radio.
Sadly, I can't remember the name of who's 'Law' this is
in Electricity and Magnetism, but it says that the net
flux passing through a closed surface is equal to the
net charge inside.
In the picture, the net charge inside the surface is ( + q - q ) = Zero.
So it must follow, as the night follows the day, the net flux
through the surface is Zero. (D)
Answer:
22 Watts
Explanation:
From the question given above, the following data were obtained:
Current (I) = 2 A
Voltage (V) = 11 V
Power (P) =?
The power of the generator can be obtained as follow:
P = IV
P = 2 × 11
P = 22 Watts
Therefore, the output power of the generator is 22 Watts