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WARRIOR [948]
3 years ago
6

A giant bat has an average mass of 250g. suppose a bat with this mass flies at 2.0m/s when it detects a giant bug

Physics
1 answer:
Anvisha [2.4K]3 years ago
8 0

Question

Determine its kinetic energy

Answer:

0.5 J

Explanation:

Kinetic energy is given by

KE=0.5mv^{2} where m is the mass and v is the speed

Substituting 250g= 0.25 Kg for mass and 2 m/s for v then

KE=0.5\times 0.25\times 2^{2}=0.5 J

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Which of the following statements is correct?
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Answer: c. Generally, metals are ductile.

Explanation:

From the options given in the question, the correct statement is that"Generally, metals are ductile.

Ductility of a metal simply means that a metal can be plastically deform before it is then fractured. It implies that metals can be drawn to thin wires. The only exception we have in this case is mercury.

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A box of mass 26 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0
Kazeer [188]

Answer:

\Delta K = 52J

Explanation:

The change in kinetic energy will be simply the difference between the final and initial kinetic energies: \Delta K=K_f-K_i

We know that the formula for the kinetic energy for an object is:

K=\frac{mv^2}{2}

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

Which for our values is:

\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

3 0
3 years ago
A mass M is suspended from a spring and oscillates with a period of 0.840 s. Each complete oscillation results in an amplitude r
iren [92.7K]

The energy becomes 0.50 times in 6.72 s.

Let E represent the oscillator's initial energy, Et be the energy's final value at time t, where A is its beginning amplitude, At amplitude at time t, be. as the oscillator's energy increases to 0.50 times its initial value. We can replace the oscillator's total energy for the energy at time t to obtain the amplitude as shown below.

Et=0.50E

1

k(4₂)² = (0.5) - kA²

(4₂)² = (0.5) A²

At = 0.71A

So, the amplitude of the oscillator becomes 0.71 times its initial ar

0.71A = = A(0.96)¹2

log(0.71)

log(0.96)

8.4

n=

So, the time taken for n oscillation is obtained as,

t = n (0.800 s)

= (8.4) (0.800)

= 6.72 s

learn more about oscillators brainly.com/question/15169199

#SPJ1

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1 year ago
How do you find the molarity of: 48.2 g of sodium carbonate in 0.500 L of solution
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