Answer:
12.76 m.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 11.9 m/s
Angle of projection (θ) = 59°
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (i.e Range) (R) =?
The horizontal distance other wise known as range from the base of the building to which the rock will strike the ground can be obtained as follow:
R = u²Sine2θ / g
R = 11.9² × Sine (2×59) / 9.8
R = 141.61 × Sine 118 / 9.8
R = 12.76 m
Therefore, the horizontal distance from the base of the building to which the rock will strike the ground is 12.76 m
<span>I believe the answer is 0.29.</span>
Answer: 6.24 km
Explanation:
Given
The magnitude of the first vector(say) 
the magnitude of the second vector(say) 
the angle between them is 
The resultant vector magnitude is given by
Answer:
The greater the velocity, the greater the Force needs to be, and the greater the fiction is
Explanation:
I don't know what you are working on so here are a few responses
It corrodes the copper by oxydation
