Answer:
1 L = 1000 cm^3
1 m^3 = 1000 L = 10^6 cm^3
1 m^3 = 10^6 g = 10^3 kg density of water
M = Density * Volume
V = 2 * 4 * 5 = 40 m^3
M = 10^3 kg / m^3 * 40 m^3 = 4.0 * 10^4 kg
<span>One property of an electron is that it has a net charge of -1. This is because the magnitude of the electric charge of an electron offsets the elementary electric charge of a proton.</span>
Answer:
W = 439998 J = 439.99 KJ
Explanation:
First, we will calculate the acceleration of the car by using the first equation of motion:
where,
a = acceleration = ?
vf = final speed = = 30 m/s
vi = initial speed = = 10 m/s
t = time = 30 s
Therefore,
a = 0.67 m/s²
Now, we will calculate the force applied by the engine:
F = ma
where,
F = force = ?
m = mass = 1100 kg
Therefore,
F = (1100 kg)(0.67 m/s²)
F = 733.3 N
Now, we will calculate the distance covered by the car by using the second equation of motion:
s = 600 m
Now, the work done (W) by engine can be calculated as follows:
W = Fs
W = (733.3 N)(600 m)
<u>W = 439998 J = 439.99 KJ</u>
The moving energy is 5,000 m/s