Answer:
The magnitude of force must you apply to hold the platform in this position = 888.89 N
Explanation:
Given that :
Workdone (W) = 80.0 J
length x = 0.180 m
The equation for this work done by the spring is expressed as:

Making the spring constant
the subject of the formula; we have:

Substituting our given values, we have:


The magnitude of the force that must be apply to the hold platform in this position is given by the formula :


F = 888.89 N
Answer:
-107 m
Explanation:
Sum of forces in the y direction:
∑F = ma
-qE = ma
a = -qE/m
a = -(1.60×10⁻¹⁹ C) (304 N/C) / (9.11×10⁻³¹ kg)
a = -53.4×10¹² m/s²
Given in the y direction:
v₀ = 0 m/s
a = -53.4×10¹² m/s²
t = 2×10⁻⁶ s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (2×10⁻⁶ s) + ½ (-53.4×10¹² m/s²) (2×10⁻⁶ s)²
Δy = -107 m
Answer:
We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.
Explanation:
Given
To determine
Kinetic Energy (K.E) = ?
We know that a body can possess energy due to its movement — Kinetic Energy.
Kinetic Energy (K.E) can be determined using the formula

where
- K.E is the Kinetic Energy (J)
now substituting m = 1.75, and v = 54 in the formula



J
Therefore, the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.
Answer:
I think it's 3) speed and direction