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zzz [600]
3 years ago
4

read each scenario below. Then select the answer that best completes each sentence. The power from a car engine is blank The pow

er of a bicycle because a car engine does the same amount of work in blank time.

Physics
1 answer:
Natali5045456 [20]3 years ago
4 0

Answer:

first blank MORE THAN

second blank LESS

Explanation:

just answered it

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Which actions are essential to active participation? Check all that apply.
erastova [34]

Answer:

2, 3, 4, 6.

Explanation:

8 0
3 years ago
Read 2 more answers
A coin is dropped from a height of 421 m. calculate the velocity of the coin after 3 s​
Keith_Richards [23]

Answer:

29.4 m.s

Explanation:

Vf = vo + at       v o = original velocity = 0 in this case

Vf = at

   = 9.81 m/s^2 * 3 = 29.4 m/s

7 0
2 years ago
A boat travels at 30 mph for a huge, solid cliff that is about 3,000 meters away. When the horn on the boat makes a toot, you ca
AleksandrR [38]

Answer:The frequency of the echo is slightly decreased

Explanation:

Given

speed of boat =30\ mph

cliff is 3000\ m away

when boat is still , suppose t is the time taken by the echo to reach observer on the boat

But as soon as boat starts moving  the distance between cliff and boat decreasing and time for echo to reach observer also decreases

and we know time \propto \frac{1}{frequency}

therefore frequency of the echo slightly decreased.

5 0
4 years ago
Vector ????⃗ has a magnitude of 16.6 and is at an angle of 50.5∘ counterclockwise from the +x‑axis. Vector ????⃗ has a magnitude
natka813 [3]

Answer:

For vector u, x component = 10.558 and  y component =12.808

unit vector = 0.636 i+ 0.7716 j

For vector v, x component = 23.6316 and y component = -6.464

unit vector = 0.9645 i-0.2638 j

Explanation:

Let the vector u has magnitude 16.6

u makes an angle of 50.5° from x axis

So u_x=ucos\Theta =16.6\times cos50.5=10.558

Vertical component u_y=usin\Theta =16.6\times sin50.5=12.808

So vector u will be u = 10.558 i+12.808 j

Unit vector u=\frac{10.558i+12.808j}{\sqrt{10.558^2+12.808^2}}=0.636i+0.7716j

Now in second case let vector v has a magnitude of 24.5

Making an angle with -15.3° from x axis

So horizontal component v_x=vcos\Theta =24.5\times cos(-15.3)=23.6316

Vertical component v_y=vsin\Theta =24.5\times sin(-15.3)=-6.464

So vector v will be 23.6316 i - 6.464 j

Unit vector of v =\frac{23.6316i-6.464}{\sqrt{23.6316^2+6.464^2}}=0.9645i-0.2638j

8 0
3 years ago
1. Does the validity of the principle of conservation of momentum depend on the validity of Newton's 3rd law of motion?​
OverLord2011 [107]
I truly believe so, that’s a definite yes
8 0
4 years ago
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