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4 years ago

An iron cube has edge 15cm long at 20c .What will be? The new surface area of a face when the temperature rises to 80c

Physics

1 answer:

grigory [225]4 years ago

3 0

Answer:

271cm^2

Explanation:

volume 1= 15^3 =3375

temp. 1. = 20+273 = 293

temp. 2. = 50+273 = 353

volume 2 =?

According to Charles law

volume is proportional to temperature

v2 = v1 * t2 / t1

v2 = 3375 * 353 / 293

v2 = 4066cm^3

v = area * length

4066 = area * 15

area = 4066/15 = 271cm^2

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A 20.0-µF capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280

natali 33 [55]

Answer

given,

Capacitance of capacitor = 20.0-µF

Voltage = 150.0-V

inductance = 0.280 m H

a) the oscillation frequency of circuit

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$f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{0.280 \times 10^{-3}\times 20 \times 10^{-6}}}$

f = 2126.9 Hz

b) $U = \dfrac{1}{2}CV^2$

$U = \dfrac{1}{2}(20\times 10^{-6})(150)^2$

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7 0

3 years ago

An engineering intern is studying the effect of temperature on the resistance of a current carrying wire. She applies a voltage

Mars2501 [29]

Answer:

I=2.80 A

Explanation:

We Know that R =R₀(1+∝ ΔT)

R=R₀ (1+3.9*10⁻³ *(61-20))

R=R₀ (1.1599)

I=V/R=V/(R₀ (1.1599)

1.4 = V/(R₀ (1.1599) ∵ equation 1

We have to calculate I when T=-88°

R =R₀(1+∝ ΔT)

R=R₀ (1+3.9*10⁻³ *(-88-20))

R=R₀ (0.5788)

I=V/(R₀ (0.5788) ∵equation 2

Dividing equation 2 by equation 1

$\frac{I}{1.4} =\frac{1.1599}{0.5788}$

I = 2.80 A

4 0

3 years ago

Read 2 more answers

A CD has a diameter of 12.0 cm. If the CD is rotating at a constant angular speed of 200 revolutions per minute, then the tangen

ozzi

Hi there!

Converting from angular velocity to tangential velocity can be done by:

v = ωr

v = tangential velocity (m/s)

ω = angular velocity (rad/sec)

r = radius (m)

Convert 12 cm to meters:

100 cm = 1 m

12 cm = 0.12 m

Now, convert rev/min to rad/sec:

${\frac{200rev}{min}} * \frac{1min}{60s} * \frac{2\pi rad}{1 rev} = 20.94 rad/sec$

v = 20.94 · 0.12 = 2.51 m/s

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