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olya-2409 [2.1K]

3 years ago

8

What happens to a bowl of hot soup when it is placed into a freezer where the air Temperature is below freezing. How does this a

pply to an open system

1 answer:

Artyom0805 [142]3 years ago

8 0

It does not it when put in the freezer it freezes the steam

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A 200kg bumper car moving 3 m/s collides head on with a 392kg bumper car moving 6m/s. After impact, the larger car continues tra

Maru [420]

Answer:

the final speed of the smaller car is 5.624 m/s

Explanation:

Given;

mass of the small car, m₁ = 200 kg

initial velocity of the small car, u₁ = 3 m/s

mass of the larger car, m₂ = 392 kg

initial velocity of the larger car, u₂ = 6 m/s

final velocity of the larger car, v₂ = 1.6 m/s

let the direction of the larger car be positive

let the direction of the smaller car be negative

Apply the principle of conservation of linear momentum to determine the final speed of the smaller car.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

200(-3) + 392(6) = 200v₁ + 392 x 1.6

-600 + 2352 = 200v₁ + 627.2

1752 = 200v₁ + 627.2

1752 - 627.2 = 200v₁

1124.8 = 200v₁

v₁ = 1124.8/200

v₁ = 5.624 m/s

Therefore, the final speed of the smaller car is 5.624 m/s

7 0

3 years ago

8–4. The tank of the air compressor is subjected to an internal pressure of 90 psi. If the internal diameter of the tank is 22 i

slamgirl [31]

Answer:

The stress S = 1935 [Psi]

Explanation:

This kind of problem belongs to the mechanical of materials field in the branch of the mechanical engineering.

The initial data:

P = internal pressure [Psi] = 90 [Psi]

Di= internal diameter [in] = 22 [in]

t = wall thickness [in] = 0.25 [in]

S = stress = [Psi]

Therefore

ri = internal radius = (Di)/2 - t = (22/2) - 0.25 = 10.75 [in]

And using the expression to find the stress:

$S=\frac{P*D_{i} }{2*t} \\replacing:\\S=\frac{90*10.75 }{2*0.25} \\S=1935[Psi]$

In the attached image we can see the stress σ1 & σ2 = S acting over the point A.

4 0

3 years ago

A man stands still on a moving escalator and a woman walks past him in the same direction as the escalator. To a stationary obse

guajiro [1.7K]

0.52 - 0.4 = 0.12
0.12 m/s

4 0

4 years ago

Read 2 more answers

The picture shows two different species of mammals that use wings to glide among tree tops. However, scientists theorize that th

AlekseyPX

Answer:

c

Explanation:

6 0

3 years ago

Read 2 more answers

Three moles of an ideal gas undergo a reversible isothermal compression at 22.0°C. During this compression, 1700 J of work is do

densk [106]

Answer:

change in entropy is - 5.7627 J/K

Explanation:

Given data

temperature = 22.0°C = 22 + 273 = 295 K

work is done = 1700 J

to find out

change in entropy

solution

we know that change in entropy = Q /T ......1

from 1st law of thermodynamic we know

Q =W for change in internal energy = 0

Q = -1700 J

so from equation 1

change in entropy = - 1700 / 295

change in entropy = - 5.7627

so change in entropy is - 5.7627 J/K

5 0

3 years ago