Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink? Explain your answer.
2 answers:
Answer:
The rock will sink in the water because it has high density than water.
Explanation:
As we know that the density of water is
And in the given question the density of the rock is .
And also it is known that any object which has higher density than the water it will sink or if it is lower density than water it will float.
Now in the given situation the density of the rock is greater than the density of the water.
Therefore, the rock will sink in the water because of high density than water.
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To solve the problem, we must use the following equation:
where
Q is the amount of heat energy absorbed by the water
m is the mass of the water
Ti and Tf are the initial and final temperature
Cs is the specific heat capacity of the water
The data we have in this problem are:
Q=40.0 kJ
m=0.500 kg
Substituting the data into the equation and re-arranging it, we find
So the final temperature of the water will be 29.1 degrees.
Answer:
a)
Explanation:
- Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:
- Since the car starts from rest, v₀ =0.
- We know the value of t = 5 sec., but we need to find the value of a.
- Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:
- Replacing a and t in (1):
- Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
- Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:
- Replacing v₀, at and t in (1), we have:
- Therefore, as the truck travels twice as far as the car, the right answer is a).
If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula
Where | A | is the magnitude of the vector and is the angle that it forms with the x axis in the opposite direction to the hands of the clock.
In this problem we know the value of Ax and Ay and we need the angle .
Vector A is in the 4th quadrant
So:
So:
So:
= -47.28 ° +360° = 313 °
= 313 °
Option 4.