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3 years ago

I only need help on #15! Thanks!

Physics

1 answer:

Vanyuwa [196]3 years ago

7 0

I would have to say that 'B' and 'D' are both correct.

Increasing the voltage that you're using to operate a circuit
causes the current in the circuit to increase. But current is
just the number of electrons that are flowing through it. So
right there, you have the increase in the number of charges.

Now, every electron that flows through the circuit gives up
some energy on the way. So if there are more electrons
making the trip, then more energy has been put into the circuit.

Jessica, I absolutely love your printing.
I wish I could print so clearly.

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If the voltage drop across the first resistor is 13.00V, then how many volts remain for the 2nd resistor?

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Answer:

2+1

Explanation:

2+1

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2 years ago

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The angular speed of the rotor in a centrifuge increases from 420 to 1420 rad/s in a time of 5.00 s. (a) Obtain the angle throug

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Answer:

a) θ = 2500 radians

b) α = 200 rad/s²

Explanation:

Using equations of motion,

θ = (w - w₀)t/2

θ = angle turned through = ?

w = final angular velocity = 1420 rad/s

w₀ = initial angular velocity = 420

t = time taken = 5s

θ = (1420 - 420) × 5/2 = 2500 rads

Again,

w = w₀ + αt

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1420 = 420 + 5α

α = 1000/5 = 200 rad/s²

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3 years ago

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In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a

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Answer: $0.084 m/s^2$

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance $d_1=8.13 km$

time taken=25 min =1500 s

initial speed $v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s$

after 8.13 km mark steve started to accelerate

speed after 60 s

$v_2=v_1+at$

$v_2=5.6+a\times 60$

distance traveled in 60 sec

$d_2=v_1\times 60+\frac{a60^2}{2}$

$d_2=336+1800 a$

time taken in last part of journey

$t_3=1663.6-1560=103.6 s$

distance traveled in this time

$d_3=v_2\times t_3$

$d_3=\left ( 5.6+a\times 60\right )103.6$

and total distance $=d_1+d_2+d_3$

$10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$a=0.084 m/s^2$

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Answer:

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Answer:

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